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3 years ago

Help? Thanks!!!!!!!!!!!

Mathematics

1 answer:

Anuta_ua [19.1K]3 years ago

4 0

Answer:

Step-by-step explanation:

You can't really show work for this, but it's A because the angles are opposite each other.

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Shown below is a trapezium, name a line perpendicular to AD.

kramer

Answer:

answer is yesterday was thrusdays

6 0

2 years ago

Bond [772]

$\frac{77}{16} = \frac{64+13}{16} = \frac{64}{16} + \frac{13}{16} =4 \frac{13}{16}=4.8125\\=4.81 \times 100~percent=481~percent\to\boxed {D}$

5 0

3 years ago

A cake company makes chocolate and vanilla cakes. The ratio of chocolate cakes to vanilla cakes is 3:4. What is the ratio of the

aleksley [76]

Answer:

4:7

Step-by-step explanation:

4:7

they make 7 cakes in total (3:4 = 7).

there are 4 vanilla cakes.

therefore, the ratio of vanilla cakes to the total number of cakes is 4:7.

6 0

2 years ago

2. Joyce waited three-quarters of an hour to

Evgen [1.6K]

Joyce waited 50 minutes waiting for the train

Step-by-step explanation:

divide 60 by 3 cause 3 quarters of an hour is 3/4 then you wanna take half an hour and add that (30 mins) getting 50 minutes

8 0

3 years ago

The function f(x) = 2x2 + 3x + 5, when evaluated, gives a value of 19. What is the function’s input value?

goldenfox [79]

$f(x)=\quad 2{ x }^{ 2 }+3x+5$

Let's called the input 'z'

When we plug 'z' in the function we get ;

$f(z)=\quad 2{ z }^{ 2 }+3z+5$

And we know that, this is equal to 19, so ;

$2{ z }^{ 2 }+3z+5=\quad 19$

Let's rearrange the equation.

$2{ z }^{ 2 }+3z+5=\quad 19\\ \\ 2{ z }^{ 2 }+3z=\quad 19-5\\ \\ 2{ z }^{ 2 }+3z=\quad 14\\ \\ 2{ z }^{ 2 }+3z-14=\quad 0$

So we have a quadratic equation here.

We'll use this formula to solve it :

$\frac { -b\pm \sqrt { { b }^{ 2 }-4ac } }{ 2a }$

The formula is used in equation formed like this :

$a{ x }^{ 2 }+bx+c=0$

In our equation,

a=2 , b=3 and c=-14

Let's plug in the values in the formula to solve,

$a=2\quad b=3\quad c=-14\\ \\ \frac { -3\pm \sqrt { 9-(4\cdot 2\cdot -14) } }{ 4 } \\ \\ \frac { -3\pm \sqrt { 9-(-112) } }{ 4 } \\ \\ \frac { -3\pm \sqrt { 9+112 } }{ 4 } \\ \\ \frac { -3\pm \sqrt { 121 } }{ 4 } \\ \\ \frac { -3\pm 11 }{ 4 }$

So,

$z=\quad \frac { -3+11 }{ 4 } \quad ,\quad \frac { -3-11 }{ 4 } \\ \\ z=\quad \frac { 8 }{ 4 } \quad ,\quad \frac { -14 }{ 4 } \\ \\ z=\quad 2,\quad -\frac { 7 }{ 2 }$

So the input can be both, 2 and $-\frac{7}{2}$

8 0

3 years ago