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navik [9.2K]
3 years ago
6

(2b) A rectangular prism measures 2 & 2/5 inches by 3 & 1/5 inches by 2 inches. How many cubes with edge length 1/5 inch

fit in the prism? *
Mathematics
1 answer:
erastova [34]3 years ago
3 0

Answer:

1920 cubes.

Step-by-step explanation

Turn both the mix numbers into improper fractions.

2 2/5 = 12/5

3 1/5 = 16/5

Then you will turn 1/5 into its reciprocal and multiply both the improper fractions by it. You can just casually multiply 2 and 5.

12/5 * 5/1 = 12

16/5 * 5/1 = 16

2 * 5 = 10

Next you multiply all together to get 1920 cubes.

(I could be missing a step. I apologize if I did.)

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5 0
3 years ago
What is the probability that a randomly selected permutation of the letters A, A, C, C, L, L, O, R, T, U would spell "calculator
kirill [66]

Answer:

See explanation

Step-by-step explanation:

Total number of letters = n! = 10

Permutation for 10 letters = n!

                                          = 10!

                                          = 10*9*8*7*6*5*4*3*2*1

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From n letters:

Number of A = 2

Number of C = 2

Number of  L = 2

A₁, A₂, C₁, C₂, L₁, L₂, O, R, T, U

Out of 3628800 permutations the word calculator can be spelled as:

C₁ A₁ L₁ C₂ U L₂ A₂ T O R

C₂ A₂ L₂ C₁ U L₁ A₁ T O R

and so on

So total number of different permutations are  

(permutation of number of letters) / permutation of (number of As * number of Cs * number of Ls)

  =  10! / (2! 2! 2 !)  

  = 10*9*8*7*6*5*4*3*2*1 / (2*1) (2*1) (2*1)

  = 3628800 / 2 * 2 * 2

  =  3628800 / 8

  =   453600

Hence probability that a randomly selected permutation of the letters A, A, C, C, L, L, O, R, T, U would spell "calculator" is:

 1 / total number of different permutations  

= 1 / 10! / (2! 2! 2 !)  

= 1/453600

= 0.000002

8 0
3 years ago
A spherical balloon was inflated such that it had a diameter of 24 centimeters. Additional helium was then added to the balloon
DanielleElmas [232]
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V= \frac{4}{3} \pi (12)^3
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3 years ago
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Answer:

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