3x + 6 = 48 (alternate angles are equal)
- 6
3x. = 42
÷3
x = 14 degrees
180-48 - 2y + 5y-9 =180
123 + 3y = 180
-123
3y = 57
÷3
y = 19 degrees
Explanation:
To find the last angle on the top straight line, do:
180 - (the 2 given angles).
So, 180 - (3x + 16, which is 48 due to alternate angles being equal). Then, minus the 2y.
(180 - 48 - 2y) & simplify => 132 - 2y
This gives you the equation for the missing angle on our top straight line.
Thus, co-interior angles add to 180. So, we add the new equation (132 - 2y) to 5y - 9.
Simplify
=> 123 + 3y (because - 2+5 =3)
and put it equal to 180. Solve for y
Hope this helps!
Answer:
y = 20°
x = 35°
Explanation:
Equation's:
1) 2y + x + 105° = 180°
2) 3x + x + 2y = 180°
Make y subject in equation 2
3x + x + 2y = 180
4x + 2y = 180
2y = 180 - 4x
y = 90 - 2x
Insert this into equation 1
2(90 - 2x) + x + 105° = 180°
180 - 4x + x + 105 = 180
-3x = -105
x = 35°
Find value of y
y = 90 - 2x
y = 90 - 2(35)
y = 20°
22 i think idk sorry if i’m wrong
One and only one line contains both A and B (assuming, that A and B do not overlap)
The four quadrants and the sign of coordinates is given as follows:
Quadrant I : (n, n ) both x and y positive.
Quadrant II : ( -n,n) = x negative and y positive.
Quadrant III : ( -n,-n) = both x and y negative.
Quadrant IV: (n, -n) = x positive and y negative.
So Based on the above concept , we can say that vertex C (-n,-n) has both x and y negative and so it lies in quadrant III.
Answer is Vertex C (-n,-n)
