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3 years ago

Which choice is equivalent to the product below?

Mathematics

2 answers:

Cloud [144]3 years ago

8 0

Answer:

equivalent of √6 . ✓3 is option a. 3√2

√6×3 = √18 = √9. √2 = 3√2

nevsk [136]3 years ago

8 0

Option (A) is the correct answer 3 √2

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ChitChat Wireless charges $0.30 per minute plus a monthly base fee. In September, Maggie used 120 minutes and her bill was $51.

SVEN [57.7K]

Answer:

$C = 0.30(m) + 15

C is bill cost

m is number of minutes used

Step-by-step explanation:

In this question, we are asked to write an equation that estimates the bill cost of Maggie’s phone bills.

We proceed as follows;

Now, let’s try and find the base fee.

We can calculate this using her bill for September.

Mathematically;

Bill = (Cost per minute * total minutes) + Base fee

Here, $0.30 per minute for 120 minutes will yield a total of 120 * 0.3 = $36

This means the base fee would be $51-$36 = $15

Now let’s say the bill is $C, and the number of minutes used is m

Mathematically;

$C = 0.30(m) + 15

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4 years ago

Find the solution set. |x|= 9<br> A. { }<br> B. {-3 , 3}<br> C. { -9, 9}<br> D. {-81, 81}

Ierofanga [76]

Answer:

C. { -9, 9}

Step-by-step explanation:

An absolute value equation has 2 solutions, a positive and a negative

|x|= 9

x= +9 and x = -9

4 0

3 years ago

Read 2 more answers

A quantity with an initial value of 6200 decays continuously at a rate of 5.5% per month. What is the value of the quantity afte

ELEN [110]

Answer:

410.32

Step-by-step explanation:

Given that the initial quantity, Q= 6200

Decay rate, r = 5.5% per month

So, the value of quantity after 1 month, $q_1 = Q- r \times Q$

$q_1 = Q(1-r)\cdots(i)$

The value of quantity after 2 months, $q_2 = q_1- r \times q_1$

$q_2 = q_1(1-r)$

From equation (i)

$q_2=Q(1-r)(1-r) \\\\q_2=Q(1-r)^2\cdots(ii)$

The value of quantity after 3 months, $q_3 = q_2- r \times q_2$

$q_3 = q_2(1-r)$

From equation (ii)

$q_3=Q(1-r)^2(1-r)$

$q_3=Q(1-r)^3$

Similarly, the value of quantity after n months,

$q_n= Q(1- r)^n$

As 4 years = 48 months, so puttion n=48 to get the value of quantity after 4 years, we have,

$q_{48}=Q(1-r)^{48}$

Putting Q=6200 and r=5.5%=0.055, we have

$q_{48}=6200(1-0.055)^{48} \\\\q_{48}=410.32$

Hence, the value of quantity after 4 years is 410.32.

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3 years ago

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PLEASE HELP ME!

Gekata [30.6K]

Answer:

He'll have $195 left

Step-by-step explanation:

$35 x 3 = $105

$300 - $105 = $195

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4 years ago

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3 years ago