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Aliun [14]
3 years ago
8

How many degrees is angle “X”?

Mathematics
2 answers:
aleksley [76]3 years ago
6 0

Answer:

The answr is 102 degrees. Here's why

Step-by-step explanation:

The square means the angle is 90 degrees. Therefore, for the big triangle, we already know 2 of the degrees, 50 and 90. A triangle's degrees add up to 180. 50+90=140. 180-140=40. This means the top angle is 40. Now finding X is easy, because we already know the other 2 points in the triangle, which are 38 and 40. Add those up, you get 78. 180-78=102, your answer. The triangle is 102 degrees.

Free_Kalibri [48]3 years ago
5 0

Answer:

X is 180 degrees

Step-by-step explanation:

Since the value of all angles within a triangle must equal 180 degrees, if you know at least two angles, you can subtract them from 180 to find the missing third angle. If you are working with equilateral triangles, divide 180 by three to find the value of X.

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Answer:

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Step-by-step explanation:

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3 years ago
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Andrei [34K]

Answer:

I got (y-7)=1/13(x+6) for point slope

and y=1/3x+13 for slope intercept form

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3 0
3 years ago
Please help me with this <br> Thanks
alexira [117]
So you make them the same common denominator
As you see, 2/10 = 8/40
2/4 = x/40, multiply by 10
2/4 = 20/40
Then add because same denominator
Now you would get:
8/40 + 20/40 = 28/40
7 0
3 years ago
Read 2 more answers
In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= 2 cm.
konstantin123 [22]

Consider right triangle ΔABC with legs AC and BC and hypotenuse AB. Draw the altitude CD.

1. Theorem: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.

According to this theorem,

BC^2=BD\cdot AB.

Let BC=x cm, then AD=BC=x cm and BD=AB-AD=3-x cm. Then

x^2=(3-x)\cdot 3,\\ \\x^2=9-3x,\\ \\x^2+3x-9=0,\\ \\D=3^2-4\cdot (-9)=9+36=45,\\ \\\sqrt{D}=\sqrt{45}=3\sqrt{5},\\ \\x_1=\dfrac{-3-3\sqrt{5} }{2}0.

Take positive value x. You get

AD=BC=\dfrac{-3+3\sqrt{5} }{2}\ cm.

2. According to the previous theorem,

AC^2=AD\cdot AB.

Then

AC^2=\dfrac{-3+3\sqrt{5} }{2}\cdot 3=\dfrac{-9+9\sqrt{5} }{2},\\ \\AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.

Answer: AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.

This solution doesn't need CD=2 cm. Note that if AB=3cm and CD=2cm, then

CD^2=AD\cdot DB,\\ \\2^2=AD\cdot (3-AD),\\ \\AD^2-3AD+4=0,\\ \\D

This means that you cannot find solutions of this equation. Then CD≠2 cm.

8 0
4 years ago
Read 2 more answers
Find the values of x and y
zhuklara [117]

You can use a tangent:

tangent=\dfrac{opposite}{adjacent}

We have opposite = 17 and adjacent = x.

\tan30^o=\dfrac{\sqrt3}{3}

substitute:

\dfrac{17}{x}=\dfrac{\sqrt3}{3}       cross multiply

x\sqrt3=(3)(17)     multiply both sides by √3

x(\sqrt3)(\sqrt3)=51\sqrt3

3x=51\sqrt3      divide both sides by 3

x=17\sqrt3

Use the Pythagorean theorem:

y^2=(17\sqrt3)^2+17^2\\\\y^2=289(\sqrt3)^2+289\\\\y^2=289\cdot3+289\\\\y^2=867+289\\\\y^2=1156\to y=\sqrt{1156}\\\\y=34

-------------------------------------------------------------------------------------------------

Other method.

30^o-60^o-90^o triangle.

The sides are in the ratio 1:2:\sqrt3\to17:y:x

Therefore

17:(2\cdot17):(17\sqrt3)\to17:34:17\sqrt3\to x=34,\ y=17\sqrt3

 


4 0
4 years ago
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