Answer:
132 N
Explanation:
Given that a 1.1 kg hammer strikes a nail. Before the impact, the hammer is moving at 4.5 m/s; after the impact it is moving at 1.5 m/s in the opposite direction. If the hammer is in contact with the nail for 0.025 s, what is the magnitude of the average force exerted by the hammer on the nail
From Newton 2nd law of motion,
Change in momentum = impulse.
Change in momentum = m( V - U )
Substitute all the parameters into the formula
Change in momentum = 1.1 ( 4.5 - 1.5 )
Change in momentum = 1.1 × 3
Change in momentum = 3.3 kgm/s
Impulse = Ft
That is,
Ft = 3.3
Substitute time t into the formula above
F × 0.025 = 3.3
F = 3.3 / 0.025
F = 132 N
Therefore, the magnitude of the average force exerted by the hammer on the nail is 132 N.
Answer:
F = 0
Explanation:
Given that,
Force acting to push a bin = 45 N
Mass of the plastic bin, m = 3 kg
The plastic bin is moving with a constant velocity.
We need to find the net force acting on the box. Constant velocity means the change in velocity is equal to 0. It means acceleration will be 0.
As a result, the force acting on the box is equal to 0.
Answer:
c) 2 blocks
Explanation:
Her displacement is the difference between her starting point and her ending point.
Let's say she starts at the origin, (0, 0).
First, she goes 13 blocks east: (13, 0)
Next, she goes 4 blocks north: (13, 4)
Then she goes 8 blocks west: (5, 4)
Then she goes 6 blocks south: (5, -2)
Finally, she goes 5 blocks west: (0, -2)
The magnitude of her displacement is the distance between her initial and final positions: 2 blocks.
Ce clasă ești sa văd daca te pot ajuta
Answer: it's 12
Explanation:
Range is the difference between the highest and lowest numbers.
33-21=12
