The position where the package strikes the ground is 136.3m.
<h3>
Time of motion of the package</h3>
Use the following kinematic equation;
h = vt + ¹/₂gt²
179 = 47t + ¹/₂(9.8)t²
179 = 47t + 4.9t²
4.9t² + 47t - 179 = 0
solve the quadratic equation using formula method;
a = 4.9, b = 47, c = -179
t = 2.9 seconds
<h3>Horizontal distance traveled by the package</h3>
X = vt
X = 47m/s x 2.9 s
X = 136.3 m
Thus, the position where the package strikes the ground is 136.3m.
Learn more about time of motion here: brainly.com/question/2364404
#SPJ1
How do you find instantaneous velocity
Select a point on a distance-time curve graph. Draw a tangent to the curve at that point. Tangent -> hypotenuse of right angled triangle. Opp/adjacent in graph units is vel at that point -> in distance and/or time
No ice is either 32 degrees Fahrenheit or 0 degrees Celsius but that's only normal ice, dry ice is a different story but I'm assuming you're talking about normal ice
We know, Potential Energy = m * g * h
Here, mass & gravity would be same, but their height will change so it will be:
ΔU = U₂ - U₁
ΔU = mgh₂ - mgh₁
ΔU = mg (h₂ - h₁)
Hope this helps!