Which number is the solution of m + 90 = 150? 60

Mathematics

2 answers:

Novay_Z [31]3 years ago

8 0

The correct answer is <u><em>m=60</em></u>

Hope This Helps!!!

-Austint1414

777dan777 [17]3 years ago

8 0

m + 90 = 150

m = 150 - 90

m = 60

yes it is 60

You might be interested in

a store is having a clearance sale where merchandise on the sales racks is reduced by 80% from the original. if a jacket was ori

posledela

The sales price is $15.2

Step-by-step explanation:

Given,

Discount = 80%

Original price = $76

Discount price = 80% of original price

$Discount\ price=\frac{80}{100}*76\\Discount\ price=\frac{6080}{100}\\Discount\ price=\$60.8$

Sale's price = Original price - Discount price

$Sale\ price= 76-60.8\\Sale\ price= \$15.2$

The sales price is $15.2

Keywords: Subtraction, percentage

Learn more about subtraction at:

#LearnwithBrainly

8 0

3 years ago

Vector donated 1/5 of yesterday's sales plus an additional $125. He gave Azul $2,225 total. How much money did the store make in

GalinKa [24]

Yesterday, the store made $10,500 in sales

7 0

3 years ago

The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airp

motikmotik

Answer:

The 95% confidence interval for the population mean rating is (5.73, 6.95).

Step-by-step explanation:

We start by calculating the mean and standard deviation of the sample:

$M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{50}(6+4+6+. . .+6)\\\\\\M=\dfrac{317}{50}\\\\\\M=6.34\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{49}((6-6.34)^2+(4-6.34)^2+(6-6.34)^2+. . . +(6-6.34)^2)}\\\\\\s=\sqrt{\dfrac{229.22}{49}}\\\\\\s=\sqrt{4.68}=2.16\\\\\\$

We have to calculate a 95% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=6.34.

The sample size is N=50.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

$s_M=\dfrac{s}{\sqrt{N}}=\dfrac{2.16}{\sqrt{50}}=\dfrac{2.16}{7.071}=0.305$