Pls help i only have a couple mins left to finish, i need help with both 1 and 2

Karls mother buys 60 party favors to give out as a fift during karls birthday party which number of guest will not let her divid

xeze [42]

THE answer is 15 just look it up

7 0

3 years ago

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Please help with this arc equation.

boyakko [2]

Answer:

Part 1) $arc\ AB=49^o$

Part 2) $arc\ ABC=204^o$

Part 3) $arc\ BAC=156^o$

Part 4) $arc\ ACB=311^o$

Step-by-step explanation:

Part 1) Find the measure of arc AB

we know that

$arc\ AB=m\angle AOB$ ----> by central angle

we have

$m\angle AOB=49^o$

therefore

$arc\ AB=49^o$

Part 2) Find the measure of arc ABC

we know that

The central angle of complete circle is equal to 360 degrees

so

$arc\ ABC=360^o-107^o-49^o=204^o$

Part 3) Find the measure of arc BAC

we know that

$arc\ BAC=arc\ BA+arc\ AC$ ----> by angle addition postulate

we have

$arc\ BA=49^o$ ---> by central angle

$arc\ AC=107^o$ ---> by central angle

so

$arc\ BAC=49^o+107^o=156^o$

Part 4) Find the measure of arc ACB

we know that

The central angle of complete circle is equal to 360 degrees

so

$arc\ ACB=360^o-arc\ AB$

substitute

$arc\ ACB=360^o-49^o=311^o$

4 0

2 years ago

g The downtime per day for a computing facility has mean 4 hours and standard deviation 0.9 hour. What assumptions must be true

Sedaia [141]

Answer:

To obtain a valid approximation for probabilities about the average daily downtime, either the underlying distribution(of the downtime per day for a computing facility) must be normal, or the sample size must be of 30 or more.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$

In this question:

To obtain a valid approximation for probabilities about the average daily downtime, either the underlying distribution(of the downtime per day for a computing facility) must be normal, or the sample size must be of 30 or more.

7 0

3 years ago

What is 7/9 - 5/18 lowest common denominator

NISA [10]

7/9 = 14/18
14-5=9
9/18=1/2

6 0

3 years ago

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What is 462 times 3 with or with out a remained

Nastasia [14]

1,386
is the answer hope this helped

5 0

2 years ago

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