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3 years ago

At what value of x do the graphs of the equations below intersect?

Mathematics

2 answers:

Zarrin [17]3 years ago

8 0

Answer:

x = 2

Step-by-step explanation:

You would find a value of y to plug into either of the equations. For example, I chose the equation 2x - y = 6. When I set it equal to y, I got y = 2x - 6
Now that I know what y is equal to, I plugged it into the second equation to get 5x + 10 (2x - 6) = -10
You then would calculate for x.
Your end result should be x = 2, which is the point that the two equations intersect

This works because the two equations are set equal to each other, making them share a common value between them.

You can also plug both of these equations into a graphing calculator, and on the graph select the command to calculate the intersection.

Hope this helped!

pychu [463]3 years ago

6 0

Answer:

x = 2

Step-by-step explanation:

Given the 2 equations

2x - y = 6 → (1)

5x + 10y = - 10 → (2)

Multiplying (1) by 10 and adding to (2) eliminates the y- term.

20x - 10y = 60 → (3)

Add (2) and (3) term by term to eliminate y, that is

25x = 50 ( divide both sides by 25 )

x = 2

The value of x at the point of intersection is x = 2

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Option C

The ratio for the volumes of two similar cylinders is 8 : 27

<h3><u>Solution:</u></h3>

Let there are two cylinder of heights "h" and "H"

Also radius to be "r" and "R"

$\text { Volume of a cylinder }=\pi r^{2} h$

Where π = 3.14 , r is the radius and h is the height

Now the ratio of their heights and radii is 2:3 .i.e

$\frac{\mathrm{r}}{R}=\frac{\mathrm{h}}{H}=\frac{2}{3}$

<em><u>Ratio for the volumes of two cylinders</u></em>

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{\pi r^{2} h}{\pi R^{2} H}$

Cancelling the common terms, we get

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\left(\frac{\mathrm{r}}{R}\right)^{2} \times\left(\frac{\mathrm{h}}{\mathrm{H}}\right)$

Substituting we get,

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\left(\frac{2}{3}\right)^{2} \times\left(\frac{2}{3}\right)$

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{2 \times 2 \times 2}{3 \times 3 \times 3}$

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{8}{27}$

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3 years ago

1. y=900(1.27)^x

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Answer:

The initial value is 900

It is experiencing exponential growth by 27%

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Exponential growth is when the multiplier is above 1.00, or above 100%, because b is determined by 1 + r if you have exponential growth, or 1 - r if you have exponential decay. You will never use negatives with exponential decay.

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