Given:
A rectangular greeting card uses a geometric design containing 4 congruent kites.
Consider the below figure attached with this question.
Length of card = 8 inches
Width of card = 4 inches
To find:
The area of one kite.
Solution:
The kites are connected to each other as shown below.
The length of a kite is:
inches
The width of a kite is:
inches
Area of a kite is:
Where, 
are diagonals of the kite.
Length and width of a kite are 4 inches and 2 inches respectively. So, the diagonals of a kite are 4 inches and 2 inches.
Using the above formula, we get
The area of a kite is 4 sq. in.
Therefore, the correct option is A.
Answer:
By changing 0.65 miles into fraction we got 65/100 and it's simplest form is 13/20 .
Answer:
35.72
Step-by-step explanation:
38% of 94:
38 * 94 = 3572
3572/100
35.72 You could round it to 35 if you want.
Have a nice day.
Answer:
The answer is below
Step-by-step explanation:
a)Given that the length of fencing available is 400 yards. This means that the perimeter of the rectangle is 400 yards.
the perimeter of a rectangle is given as:
Perimeter = 2(length + width) = 2(l + w)
Hence;
400 = 2(l + w)
200 = l + w
l = 200 - w
The area of a rectangle is given as:
Area = length × width
Area = (200 - w) × w
Area = 200w - w²
b) For a quadratic equation y = ax² + bx + c. it has a maximum at x = -b/2a
Hence, for the area = 200w - w² a=-1, b = 200, the maximum width is at:
w = -b/2a = -200/2(-1) = -200/-2 = 100
A width of 100 yard has the largest area
c) l = 200 - w = 200 - 100 = 100 yards
Area = l × w = 100 × 100 = 10000 yd²
The maximum area is 10000 yd²
Answer:
A: the same line
Step-by-step explanation:
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