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2 years ago

Write the expression in simplest form.

Mathematics

1 answer:

stiv31 [10]2 years ago

7 0

Answer:

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What is the square root of 248 + square root of 63

enyata [817]

Answer:

1) √248 = ± 15.7480157

2)√63 = ± 7.93725393

Step-by-step explanation:

7 0

2 years ago

- 3x + 4 and passes through the point (2,5)

Anuta_ua [19.1K]

Answer:

y=(x+13)/3

Step-by-step explanation:

the question is not quite clear, i think u mean y= -3x + 4

then, the slope of the line perpendicular to the given line is m1.m2= -1, hence, -3.m2= -1 m2 = 1/3

y-5=1/3(x-2) y=x/3+13/3 or y=(x+13)/3

6 0

2 years ago

What is 1504.92 x8%x 1/12=

valentinak56 [21]

Answer:

10.0328

Step-by-step explanation:

this is the answer

4 0

3 years ago

At what angle does a diffraction grating produce a second-order maximum for light having a first-order maximum at 20.0 degrees?

hichkok12 [17]

Answer:

At 43.2°.

Step-by-step explanation:

To find the angle we need to use the following equation:

$d*sin(\theta) = m\lambda$

Where:

d: is the separation of the grating

m: is the order of the maximum

λ: is the wavelength

θ: is the angle

At the first-order maximum (m=1) at 20.0 degrees we have:

$\frac{\lambda}{d} = \frac{sin(\theta)}{m} = \frac{sin(20.0)}{1} = 0.342$

Now, to produce a second-order maximum (m=2) the angle must be:

$sin(\theta) = \frac{\lambda}{d}*m$

$\theta = arcsin(\frac{\lambda}{d}*m) = arcsin(0.342*2) = 43.2 ^{\circ}$

Therefore, the diffraction grating will produce a second-order maximum for the light at 43.2°.

I hope it helps you!

6 0

2 years ago

Given: Rhombus ABCD. If mBAD is 64 degrees, then the mDCA is ___ degrees.

Marta_Voda [28]

Answer: 32 degrees

Step-by-step explanation:

6 0

1 year ago

Write the expression in simplest form.​

Write the expression in simplest form.