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mestny [16]
3 years ago
14

An automobile light has a 1.0-a current when it is connected to a 12-v battery. determine the resistance of the light.

Physics
1 answer:
Elis [28]3 years ago
3 0
<span>Resistance of automobile light  is equal to 12 ohms.
</span>Resistance = Voltage / Current
where
Voltage = 12 volts
Current = 1.0 Amperes
Resistance = 12 volts/ 1.0 amperes
Resistance = 12 ohms.
Automobile light has 12 ohms resistance  when it is connected to 12volts battery with 1.0 ampere current.
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A coil lies flat on a level tabletop in a region where the magnetic field vector points straight up. The magnetic field suddenly
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Answer:

c. Clockwise

Explanation:

As per FARADAY's the rate of change in magnetic flux linked with a coil will induce EMF in the coil and this will result the induce current in the coil.

Here we know that the direction of induced current in the closed loop is in such a way that the magnetic flux due to induced current always oppose the flux due to which it is induced

So we can say that if the flux linked with the coil will increase with time then flux of induced current will be in opposite direction to oppose the increasing flux.

So here when magnetic field becomes stronger then the induced current is in such a way that will always oppose the increasing flux of magnetic field

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c. Clockwise

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3 years ago
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katrin2010 [14]

Answer:

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Explanation:

6 0
3 years ago
When a mass of 29 g is attached to a certain spring, it makes 20 complete vibrations in 3.1 s. What is the spring constant of th
never [62]

Answer:

The spring constant of the spring is 47.62 N/m

Explanation:

Given that,

Mass that is attached with the spring, m = 29 g = 0.029 kg

The spring makes 20 complete vibrations in 3.1 s. We need to find the spring constant of the spring. We know that the number of oscillations per unit time is called frequency of an object. So,

f=\dfrac{20}{3.1}

f = 6.45 Hz

The frequency of oscillator is given by :

f=\dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}}

k is the spring constant

k=4\pi^2f^2m

k=4\pi^2\times (6.45)^2\times 0.029

k = 47.62 N/m

So, the spring constant of the spring is 47.62 N/m. Hence, this is the required solution.

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3 years ago
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Explanation:

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3 years ago
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4 years ago
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