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IRISSAK [1]
3 years ago
11

PLEASE HELP ASAP Which one of the following is a step used for balancing chemical equations?

Physics
1 answer:
scZoUnD [109]3 years ago
3 0

Answer:

C. Count the atoms in each substance in the reactants and products.

Explanation:

A chemical reaction can be defined as a chemical process which typically involves the transformation or rearrangement of the atomic, ionic or molecular structure of an element through the breakdown and formation of chemical bonds to produce a new compound or substance.

In order for a chemical equation to be balanced, the condition which must be met is that the number of atoms in the reactants equals the number of atoms in the products.

This ultimately implies that, the mass and charge of the chemical equation are both balanced properly.

In Chemistry, all chemical equation must follow or be in accordance with the Law of Conservation of Mass, which states that mass can neither be created nor destroyed by either a physical transformation or a chemical reaction but transformed from one form to another in an isolated (closed) system.

One of the step used for balancing chemical equations is to count the atoms in each substance in the reactants and products.

For example;

NH3 + O2 -----> NO + H2O

The number of atoms in each chemical element are;

For the reactant side:

Nitrogen, N = 1

Hydrogen, H = 3

Oxygen, O = 2

For the product side;

Nitrogen, N = 1

Hydrogen, H = 2

Oxygen, O = 2

When we balance the chemical equation, we would have;

NH3 + 3O2 -----> 4NO + 2H2O

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The springs of a 1500 kg car compress 5.00 mm when its 68 kg driver gets into the driver's seat. Part A If the car goes over a b
elena-s [515]

Answer:

the frequency of the oscillation is 1.5 Hz

Explanation:

Given;

mass of the spring, m = 1500 kg

extention of the spring, x = 5 mm = 5 x 10⁻³ m

mass of the driver = 68 kg

The weight of the driver is calculated as;

F = mg

F = 68 x 9.8 = 666.4 N

The spring constant, k, is calculated as;

k = F/m

k = (666.4 N) / (5 x 10⁻³ m)

k = 133,280 N/m

The angular speed of the spring is calculated;

\omega = \sqrt{\frac{k}{m} } \\\\\omega = \sqrt{\frac{133280}{1500} } = 9.426 \ rad/s

The frequency of the oscillation is calculated as;

ω = 2πf

f = ω / 2π

f = (9.426) / (2π)

f = 1.5 Hz

Therefore, the frequency of the oscillation is 1.5 Hz

6 0
3 years ago
When a 4.25 kg object is placed on top of a vertical spring, the spring compresses a distance of 2.62 cm. what is the force cons
ANTONII [103]
The force applied to the spring is the weight of the object that compresses it, so it is equal to:
W=mg=(4.25 kg)(9.81 m/s^2)=41.7 N

Because of this force, the spring compresses by x=2.62 cm=0.0262 m. Using Hook's law,
F=kx,
since we know the intensity of the force (the weight W) and the compression of the spring, x, we can find k, the spring constant:
k= \frac{F}{x}= \frac{W}{x}= \frac{41.7 N}{0.0262 m}   =1591.6 N/m
6 0
3 years ago
Convert 15*c in Fahrenheit
balandron [24]

Answer:

it is 59 degrees Fahrenheit

5 0
2 years ago
Read 2 more answers
Diego hypothesizes that the Earth wobbles on its axis in a pattern that is repeated every 20,000 years.
DedPeter [7]

Answer:

D. make a model

Explanation:

3 0
3 years ago
A boy throws a stone straight upward with an initial
Dominik [7]

Answer:

14.8m

Explanation:

Given parameters:

Initial speed  = 17m/s

Unknown:

Maximum height  = ?

Solution:

At the maximum height, the final speed will be 0m/s;

 We use of the kinematics equation to solve this problem.

     V²   = U²   - 2gH

V is the final velocity

U is the initial velocity

g is the acceleration due to gravity

H is the height

         0²   = 17²  -  (2  x 9.8 x h )

          0 = 289  - (9.6h)

         -289  = -19.6h

            h  = 14.8m

5 0
3 years ago
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