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4 years ago

7

Quito, Ecuador has an average altitude of 9,350 ft. On a standard day, pressure gage A in a laboratory experiment reads 63 kPa a

nd gage B reads 105 kPa. Express these readings in gage pressure or vacuum pressure, whichever is appropriate.

1 answer:

kolezko [41]4 years ago

8 0

Explanation:

Below is an attachment containing the solution.

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Define stress engineering science

kiruha [24]

Answer:

Stress, in physical sciences and engineering, force per unit area within materials that arises from externally applied forces, uneven heating, or permanent deformation and that permits an accurate description and prediction of elastic, plastic, and fluid behaviour.

I hope it's helpful!

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3 years ago

2 Select the correct answer. Javed suffers from a severe food allergy. Which device should Javed always carry? A. inhaler B. epi

Slav-nsk [51]

The best answer would be:

B. Epi pen

Here is more about it:

An epi pen injects epinephrine into the body to counteract the effects of an allergic reaction. Epinephrine helps narrow blood vessels and open up the airways. This can be used for food allergies, insect bites, and some other allergens. It is very effective and immediately works, but it is short-lived, so seeking medical attention after is still needed.

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3 years ago

A block of plastic in the shape of a rectangular solid that has height 8.00 cm and area A for its top and bottom surfaces is flo

kifflom [539]

Answer:

0.35 kg

Explanation:

8 cm = 0.08 m

For the block to stay balance, the buoyancy force must be the same as gravity that pulls it down.

Let mass of the block be M, then the gravity would be Mg

Let water density be $\rho_w = 1000 kg/m^3$ , the buoyancy force would be the weight of water that is displaced by the submerged block.

For example, when there is no coin, block is $h_0 = 0.0312m$ submerged. The weight of water displaced must be

$W_0 = Ah_0\rho_wg = 0.0312A1000g = 31.2Ag$

Which is also the weight of block, of Mg

Therefore M = 31.2A. (1)

As coins are stacked on top of block, h increase, so as weight of water displaced and total weight of block and coins. Now let m be the total weight of coins. The gravity of block and weight must be (M+m)g. And the weight of water displaced is:

$W = Ah\rho g = (M + m)g$

$h = \frac{M}{A\rho} + \frac{m}{A\rho}$

Since the linear plot of h vs m has a slope of 0.089 m/kg, we can interpret it as

$\frac{1}{A\rho} = 0.089$

$A = \frac{1}{0.089\rho} = \frac{1}{89} = 0.011 m^2$

So from the eq. (1) we can solve for M = 31.2A = 0.35 kg

8 0

3 years ago

Which of the following is not used when prediciting volcanic erruptions

bixtya [17]

Answer:

earthquake activity is the answer

3 0

4 years ago

A cart traveling at 0.3 m/s collides with stationary object. After the collision, the cart rebounds in the opposite direction. T

padilas [110]

Answer:

Explanation:

First case

A cart speed is 0.3m/s. i.e the initial velocity is u=0.3m/s

It collide with a stationary body, then after collision the ball rebounds and move in opposite direction. This shows that the ball have a velocity after impulse let say v

Then, impulse is given as the change in linear momentum of a body

Impulse =m∆v

I=m(v-u)

Note, momentum is a vector quantity.

I=m(v--u)

I=m(v+u)

I=m(v+0.3)

I¹=0.3m+mv. Equation 1

Second case

A cart speed is 0.3m/s. i.e the initial velocity is u=0.3m/s

It collide with a stationary body, then after collision the ball is at rest, this show that the final velocity is v=0

Then, impulse is given as the change in linear momentum of a body

Impulse =m∆v

I=m(v-u)

Note, momentum is a vector quantity.

I=m(v--u)

I=m(v+u)

In this case v=0 u=0.3m/s

I=m(0+0.3)

I²=0.3m. Equation 2

If we compare impulse 1 (I¹) to impulse 2 (I²)

Subtract equation 2 from 1

We have, I¹ - I² =0.3m+mv -0.3m

I¹ - I² =mv

I¹ =mv+I²

We notice that the first impulse (I¹) is greater than second impulse (I²) by mv.

The correct answer is A

5 0

3 years ago