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Lemur [1.5K]
3 years ago
14

Write the fraction as a decimal and a percent 5/8 equals what and equals ?%​

Mathematics
2 answers:
8090 [49]3 years ago
7 0

Answer:

.625   /    62.5%

Step-by-step explanation:

hope this helps :)

nadya68 [22]3 years ago
5 0

Answer:

0.625

62.5%

Step-by-step explanation:

5/8 = 0.625

.625 = 62.5%

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aleksandrvk [35]
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4 0
3 years ago
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What is the slope of the line?
Talja [164]

Answer:

\displaystyle m=1

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Slope Formula: \displaystyle m=\frac{y_2-y_1}{x_2-x_1}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Find points from graph.</em>

Point (-1, 0)

Point (0, 1)

<u>Step 2: Find slope </u><em><u>m</u></em>

Simply plug in the 2 coordinates into the slope formula to find slope<em> m</em>

  1. Substitute in points [SF]:                    \displaystyle m=\frac{1-0}{0--1}
  2. [Fraction] Simplify:                              \displaystyle m=\frac{1-0}{0+1}
  3. [Fraction] Subtract/Add:                     \displaystyle m=\frac{1}{1}
  4. [Fraction] Divide:                                \displaystyle m=1
7 0
3 years ago
Use the theorem in Sec. 28 to show that if f (z) is analytic and not constant throughout a domain D, then it cannot be constant
alexandr1967 [171]

Answer:

The value of f(z) is not constant in any neighbourhood of D. The proof is as explained in the explaination.

Step-by-step explanation:

Given

For any given function f(z), it is analytic and not constant throughout a domain D

To Prove

The function f(z) is non-constant constant in the neighbourhood lying in D.

Proof

1-Assume that the value of f(z)  is analytic and has a constant throughout some neighbourhood in D which is ω₀

2-Now consider another function F₁(z) where

F₁(z)=f(z)-ω₀

3-As f(z) is analytic throughout D and F₁(z) is a difference of an analytic function and a constant so it is also an analytic function.

4-Assume that the value of F₁(z) is 0 throughout the domain D thus F₁(z)≡0 in domain D.

5-Replacing value of F₁(z) in the above gives:

F₁(z)≡0 in domain D

f(z)-ω₀≡0 in domain D

f(z)≡0+ω₀ in domain D

f(z)≡ω₀ in domain D

So this indicates that the value of f(z) for all values in domain D is a constant  ω₀.

This contradicts with the initial given statement, where the value of f(z) is not constant thus the assumption is wrong and the value of f(z) is not constant in any neighbourhood of D.

6 0
3 years ago
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Tanzania [10]

Answer:

d is the answer

Step-by-step explanation:

8 0
2 years ago
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Genevieve wants to verify that }(5x-20)-(4x-8) is equivalent to x. Which procedure can Genevieve follow to determine if
Gnom [1K]

They aren't equivalent

<h2>Explanation:</h2>

In order to determine whether the expression:

(5x-20)-(4x-8)

is equivalent to:

x

Genevieve needs to follow these steps:

Step 1. Get rid parentheses

5x-20-4x+8

Step 2. Combine like terms

5x-4x-20+8

Step 3. Solve

x-12

So:

x\neq x-12

Therefore, these two expressions aren't equivalent.

<h2>Learn more:</h2>

Writing expressions: brainly.com/question/13894833#

#LearnWithBrainly

4 0
3 years ago
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