Answer:
approx 58 yard we can determine it by pithagoras theorem
Answer:
≈9
Step-by-step explanation:
V= πr^2(h/3)
1356.48= πr^2(16/3)
r= 8.99 or about 9
6v-5/8=7/8
6v=12/8
v=12/8÷6
v=.25
Dish A has n₁ = 1.75 x 10¹⁸ bacteria.
Dish B has n₂ = 6.25 x 10¹⁵ bacteria.
Calculate n₁/n₂.

The number of times that the number of bacteria in dish A is greater than the number of bacteria in dish B is 2.8 x 10² in standard notation.
Answer: 2.8 x 10²