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tester [92]
3 years ago
10

H/7 =27 can some one answer this pls

Mathematics
1 answer:
Lesechka [4]3 years ago
3 0

Answer:

h=189

Step-by-step explanation:

solve for H by simplifying both sides of the equation, then isolating the variable.

hope this helped

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You have 600 feet of fencing to enclose a rectangular plot that borders on a river. If you do not fence the side along the river
inn [45]

Answer:

The length and width of plot is L=300\:ft, W=150\:ft

Largest area of the plot is A=45000 ft^{2}

Step-by-step explanation:

Assume width as x and length as y. Given that length of fencing is 600 feet and fencing is enclosed on 3 sides. So perimeter is given as,

Perimeter = width + length + width

Substituting the value,  

600=x+y+x

600= 2x+y  ….1

Now area of fence of rectangular box is given as follows,  

A=xy  ….2

Solving equation 1 for y, subtracting 2x from both sides,  

600-2x= y

Substituting the value in equation 2,  

A=x\left (600-2x  \right )

Simplifying

A=600x-2x^{2}

Rewriting,  

A=-2x^{2}+600x

Above equation looks like quadratic equation f\left ( x \right )=ax^{2}+bx+c whose graph looks like parabola.  

Comparing equation f(x) and A values of a, b and c are, a=-2,b=600 and c=0.  

Now maximum of f\left ( x \right ) occurs at vertex.  

The x coordinate of the vertex is given as -\dfrac{b}{2a}

Substituting the values,  

x=-\dfrac{600}{2\left (-2  \right )}

Simplifying,  

x=\dfrac{600}{4}

x=150

So width of plot is 150 feet.  

Now to calculate value of length by using equation 1,

600= 2x+y

Substituting the values,

600= 2\left (150  \right )+y

600= 300+y

Subtracting 300 from both sides,

300= y

So length of plot is 300 ft.

The y coordinate of the vertex is given as y=f\left ( -\dfrac{b}{2a} \right ) which also means, y=f\left ( 150 \right )

\therefore A=-2\left (150  \right )^{2}+600\left (150  \right )

Simplifying,  

\therefore A=-2\left (22500  \right )^{2}+600\left (150  \right )

\therefore A=-45000+90000

\therefore A=45000

So, area of the plot will be A=45000 ft^{2}

7 0
3 years ago
I NEED HELP WITH QUESTION PLEASE!!<br> What is the inverse of f(x)<br> (x) = (x-4)² for x ≥ 4?
goblinko [34]

Answer:

4th choice \bold{f^{-1}(x) = \sqrt{x} + 4}

Step-by-step explanation:

<u>Definition of the inverse of a function</u>

A function g is the inverse of a function f if whenever y=f(x) then x=g(y). In other words, applying f and then g is the same thing as doing nothing. We can write this in terms of the composition of f and g as g(f(x))=x. The domain of f becomes the range of g and the range of f becomes the domain of g

To solve for the inverse of the function f(x) =\left(x-4\right)^2

Let y=\left(x-4\right)^2

\mathrm{Replace}\:x\:\mathrm{with}\:y \text{ and replace }\:y\:\mathrm{with}\:x

x=\left(y-4\right)^2

Switch sides
\left(y-4\right)^2=x

Take square roots on both sides
y-4=\pm\sqrt{x}

Add 4 on both sides to solve for y

y = \pm\sqrt{x} + 4

We have two solutions

y=\sqrt{x}+4,\:y=-\sqrt{x}+4

To determine which one of these to be chosen not that in the given choices we can eliminate the first two since x cannot be negative

The third choice can also be eliminated since
-\sqrt{x} + 4 is a decreasing function for x \ge 0

So the last answer choice is correct and the inverse off(x) = (x-4)^2

is given by  f^{-1}(x) = \sqrt{x} + 4

Answer:4th choice \bold{f^{-1}(x) = \sqrt{x} + 4}

Note

Domain of  (x-4)² is [4, ∞) since x ≥ 4 and (x-4)²  cannot be negative

Range of (x-4)²  is [0,  ∞)

Domain of \sqrt{x}\:+\:4 is [0, ∞)

Range of \sqrt{x}\:+\:4 is [4, ∞)

so indeed the domain of (x-4)² has become the range of \sqrt{x}\:+\:4 and the range of (x-4)² has become the domain of \sqrt{x}\:+\:4

5 0
1 year ago
Factor the GCF: −12x3y5 − 9x2y2 + 12xy3
Luba_88 [7]
<span>−12x3y5 − 9x2y2 + 12xy3</span>
-3xy^2(4x^2y^3+3x-4y)
6 0
3 years ago
Plz help asappppp I’ll give brainliest
Elena L [17]

Answer: c I think

Step-by-step explanation:

7 0
2 years ago
Which of the following are solutions to the equation sinx cosx = (sqrt of 3)/4? Check all that apply.
Dmitriy789 [7]

\sin x \cos x = \dfrac{\sqrt 3}{4}


2 \sin x \cos x = \dfrac{\sqrt 3}{2}


\sin 2x = \sin \frac \pi 3


2x = \frac \pi 3 + 2 \pi n \textrm{ or } 2x = (\pi - \frac \pi 3) + 2 \pi n \quad \textrm{integer } n


x = \frac \pi 6 +  \pi n \textrm{ or } x =  \frac \pi 3 +  \pi n


Choices A and C



6 0
3 years ago
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