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RUDIKE [14]
3 years ago
10

D%20" id="TexFormula1" title=" {2}^{2} \times {2}^{3} \div {2}^{4} " alt=" {2}^{2} \times {2}^{3} \div {2}^{4} " align="absmiddle" class="latex-formula">
find the value of a ​
Mathematics
1 answer:
vodka [1.7K]3 years ago
4 0
A= 2 to the power of -1
Because if it's the same base no in multiplication we add the indices and in division we subtract the indicies
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Answer:

Step-by-step explanation:

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4 0
4 years ago
Read 2 more answers
Someone please explain (:
GaryK [48]

Answer:

a.) 1.38 seconds

b.) 17.59ft

Step-by-step explanation:

h(t) = -16t^2 + 22.08t + 6

if we were to graph this, the vertex of the function would be the point, which if we substituted into the function would give us the maximum height.

to find the vertex, since we are dealing with something called "quadratic form" ax^2+bx+c, we can use a formula to find the vertex

-b/2a

b=22.08

a=-16

-22.08/-16, we get 1.38 when the minuses cancel out. since our x is time, it will be 1.38 seconds

now since the vertex is 1.38, we can substitute 1.38 into the function to find the maximum height.

h(1.38)= -16(1.38)^2 + 22.08t + 6 -----> is maximum height.

approximately = 17.59ft -------> calculator used, and rounded to 2 significant figures.

for c the time can be equal to (69+sqrt(8511))/100, as the negative version would be incompatible since we are talking about time. or if you wanted a rounded decimal, approx 1.62 seconds.

7 0
3 years ago
Read 2 more answers
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