Y = 0.213x – 352.0 <span> represents this linear model shown in the data table.
Plug in the values of x into the equation for a double check.
Let's try 1980.
</span><span>y = 0.213(1980) – 352.0
</span>y = 69.74
which is closest to the 70.1 whereas other options do not satisfy the condition.
1540.5 .
V=PI*R^2*H/3=3.14*9.5^2*5.433=1540;5
Percent increase
find increase first
10500 to 11300
11300-10500=800
so
percent increase
change/original
origianal=10500
change=800
800/10500=8/105=0.0761
percent means parts out of 100
0.0761/1 times 100/100=7.61/100=7.61%
rond 7.61% to tenth or to 7.6%
7.6%
Let events
A=Nathan has allergy
~A=Nathan does not have allergy
T=Nathan tests positive
~T=Nathan does not test positive
We are given
P(A)=0.75 [ probability that Nathan is allergic ]
P(T|A)=0.98 [probability of testing positive given Nathan is allergic to Penicillin]
We want to calculate probability that Nathan is allergic AND tests positive
P(T n A)
From definition of conditional probability,
P(T|A)=P(T n A)/P(A)
substitute known values,
0.98 = P(T n A) / 0.75
solving for P(T n A)
P(T n A) = 0.75*0.98 = 0.735
Hope this helps!!
