Given that Trent's watch runs at half the speed it should run, this implies that
for every hour passed, his watch moves by half an hour.
Hence, for every half-hour passed, Trent's watch moves by 15 minutes.
Hence, when the real time is 10:30 am, Trent's watch will show 9:15 am.
The radius of the circle is 3 cm.
<u>Step-by-step explanation:</u>
Refer the attached diagram, the circle with centre O. In that given, AB is tangent given as 4 cm and distance of point from the circle, OA = 5 cm
As AB is tangent, OB (radius of circle) is perpendicular to AB (tangent at any point of circle). Therefore the angle of OBA is 90 degree.
Also, triangle OAB is a right angled triangle (refer attached diagram). By using Pythagoras theorem in right angled triangle,


Substitute the given values in the above expression, we get


Taking square root on both side, we get
Radius of the circle, OB = 3 cm
Answer:
D. 972 ft^2
Step-by-step explanation:
SA = 2B + PH
where SA = total surface area of the prism,
B = area of a base
P = perimeter of the base
H = height of the prism
SA = 2 * bh/2 + (15 ft + 12 ft + 9 ft)(24 ft)
SA = (9 ft)(12 ft) + (15 ft + 12 ft + 9 ft)(24 ft)
SA = 972 ft^2
Answer:
156.5375 cm
Step-by-step explanation:
The function used to estimate the height is F(x)
F(x) = 2.75x + 71.48
The humerus is xcm long. When x = 30.93cm, we put x = 30.93 into the function F(x)
F(30.93) = 2.75(30.93) + 71.48
= 85.0575 + 71.48
= 156.5375 cm(4 decimal places)