Step-by-step explanation:
2×9n=18n
2×-6=-12
52-12+18n= 38 +18n
2×7n=14n
8×2=16
14n+16
38+18n=14n+16
subtract 14n from 14n and 18n
38+4n=16
subtract 38 from 38 and 16
4n=-22
divide each side by 4
n= -5.5
Answer:
In other words, the base must be at least 9 feet long.
Step-by-step explanation:
The schools wants the height of the triangle to be eight feet, and the area of the logo to be at least 36 square feet.
Recall that the area of a triangle is given by:
Since we want to area to be at least 36 square feet:
We are given that the height is eight feet. Substitute:
Simplify:
Divide both sides by four. Hence, our inequality is:
In words, this means that the base must be at least 9 feet long.
Part 1: getting the area of the entrance
The entrance has a trapezoid shape.
Area of trapezoid can be calculated using the following rule:
Area of trapezoid = average base * height
The aveage base = (b1+b2)/2 = (8+16)/2 = 12 ft
height of trapezoid = 4 ft
Therefore:
area of entrance = 12*4 = 48 ft^2
Part 2: getting the area of the house:
area of house = area of back porch + area of side deck + area of play room + area of entrance
i- getting the area of the back porch:
The back porch is a square with side length = 6 ft
Therefore:
area of back porch = 6*6 = 36 ft^2
ii- getting the area of side deck:
The side deck is a rectangle whose length is 14 ft and width is 3 ft
Therefore:
area of side deck = 14*3 = 42 ft^2
iii- getting the area of play room:
The play room is a rectangle whose length is 14 ft and width is 16 ft
Therefore:
area of play room = 14*16 = 224 ft^2
iv- area of entrance is calculated in part 1 = 48 ft^2
Based on the above:
area of house = 36 + 42 + 224 + 48 = 350 ft^2
hope this helps :)
Answer:
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Step-by-step explanation:
F(x)=(x)-1 I think that’s the answer but use Desmos to figure out
