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Ierofanga [76]
3 years ago
6

Which angle pair is a pair of corresponding angles?

Mathematics
1 answer:
GREYUIT [131]3 years ago
5 0

Answer:

B - <em>∠b and ∠f</em>

Step-by-step explanation:

Corresponding angles are the angles in matching corners of the intersections in the traversal. Since <em>∠b</em> and <em>∠f</em> are in the same position relative to the intersection, they are corresponding.

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What values do you need to know to create a box plot? Select all that apply interquartile range
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B., C., and E or 2, 3, and 5

Step-by-step explanation:

I did it and got it right.

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Let x △ y be defined by x △ y=x−5y. What is the value of 3 △  (−4)
TEA [102]

x\Delta y=x-5y\\\\3\Delta(-4)\qquad\text{put the values x = 3 and y = -4 to the expression x - 5y}:\\\\3\Delta(-4)=3-5(-4)=3+20=23

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Your store cost on a dozen eggs is $0.75, and your retail price is $2.99. You are having a promotion that discounts the
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3 years ago
Please answer quick brain list on cludded ​
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4 0
2 years ago
Find the angle between the given vectors. Round your answer, in degrees, to two decimal places. u=⟨2,−6⟩u=⟨2,−6⟩, v=⟨4,−7⟩
NISA [10]

Answer:

\theta = 108.29

Step-by-step explanation:

Given

u =

v =

Required:

Calculate the angle between u and v

The angle \theta is calculated as thus:

cos\theta = \frac{u.v}{|u|.|v|}

For a vector

A =

A = a * b

cos\theta = \frac{u.v}{|u|.|v|} becomes

cos\theta = \frac{.}{|u|.|v|}

cos\theta = \frac{2*6+4*-7}{|u|.|v|}

cos\theta = \frac{12-28}{|u|.|v|}

cos\theta = \frac{-16}{|u|.|v|}

For a vector

A =

|A| = \sqrt{a^2 + b^2}

So;

|u| = \sqrt{2^2 + 6^2}

|u| = \sqrt{4 + 36}

|u| = \sqrt{40}

|v| = \sqrt{4^2+(-7)^2}

|v| = \sqrt{16+49}

|v| = \sqrt{65}

So:

cos\theta = \frac{-16}{|u|.|v|}

cos\theta = \frac{-16}{\sqrt{40}*\sqrt{65}}

cos\theta = \frac{-16}{\sqrt{2600}}

cos\theta = \frac{-16}{\sqrt{100*26}}

cos\theta = \frac{-16}{10\sqrt{26}}

cos\theta = \frac{-8}{5\sqrt{26}}

Take arccos of both sides

\theta = cos^{-1}(\frac{-8}{5\sqrt{26}})

\theta = cos^{-1}(\frac{-8}{5 * 5.0990})

\theta = cos^{-1}(\frac{-8}{25.495})

\theta = cos^{-1}(-0.31378701706)

\theta = 108.288386087

<em></em>\theta = 108.29<em> (approximated)</em>

4 0
2 years ago
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