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3 years ago

Antonio completed the right column of the table to help him find the sum of 2/9 and 1/5.

Mathematics

1 answer:

Blizzard [7]3 years ago

5 0

Answer:

Step 1 is the first error

Step-by-step explanation:

Given

$\frac{2}{9} + \frac{1}{5}$

Required

Which step contains the first error?

From the attachment, the first step is the first error.

This is so because the fractions can not be written as a fraction with a denominator of 14

Solving further:

$\frac{2}{9} + \frac{1}{5}$

Find Common Denominator 45

$\frac{2*5}{9*5} + \frac{1*9}{5*9}$

$\frac{10}{45} + \frac{9}{45}$

Add:

$\frac{10 + 9}{45}$

$\frac{19}{45}$

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maria [59]

Answer:

First option: $3x^2-5x=-8$

Second option: $2x^2=6x-5$

Fourth option: $-x^2-10x=34$

Step-by-step explanation:

Rewrite each equation in the form $ax^2+bx+c=0$ and then use the Discriminant formula for each equation. This is:

$D=b^2-4ac$

1) For $3x^2-5x=-8$ :

$3x^2-5x+8=0$

Then:

$D=(-5)^2-4(3)(8)=-71$

Since $D$ this equation has no real solutions, but has two complex solutions.

2) For $2x^2=6x-5$ :

$2x^2-6x+5=0$

Then:

$D=(-6)^2-4(2)(5)=-4$

Since $D$ this equation has no real solutions, but has two complex solutions.

3) For $12x=9x^2+4$ :

$9x^2-12x+4=0$

Then:

$D=(-12)^2-4(9)(4)=0$

Since $D=0$ this equation has one real solution.

4) For $-x^2-10x=34$ :

$-x^2-10x-34=0$

Then:

$D=(-10)^2-4(-1)(-34)=-36$

Since $D$ , this equation has no real solutions, but has two complex solutions.

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3 years ago

Simplify (2m^6)^3.

labwork [276]

Answer:

B. 8m ^ 18

Step-by-step explanation:

(2m ^6)^3 is the same as ;

(2 ^1 × m ^ 6) ^ 3.....multiply the powers 1 and 6 by 3

2 ^ (1×3) × m ^ (6×3).....this equals;

2 ^ 3 × m ^ 18

8m^18

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