1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
xz_007 [3.2K]
2 years ago
12

The quality control team of a company checked 800 digital cameras for defects. The team found that 20 cameras had lens defects,

25 cameras had charging defects, and 6 cameras had both defects. What is the probability that a camera has a lens defect given that it has a charging defect?
Mathematics
1 answer:
dmitriy555 [2]2 years ago
6 0

Answer:

0.025

Step-by-step explanation:

-This is a conditional probability problem.

-Let L denote lens defect and C charging defect.

#We first calculate the probability of a camera having a lens defect;

P(lens)=\frac{Lens}{Total}\\\\=\frac{20}{800}\\\\=0.025

#Calculate the probability of a camera having a charging defect:

P(Charging)=\frac{Charging}{Total}\\\\=\frac{25}{800}\\\\=0.03125

The  the probability that a camera has a lens defect given that it has a charging defect is calculated as:

P(L|C)=\frac{P(C)P(L)}{P(C)}\\\\=\frac{0.025\times 0.03125}{0.03125}\\\\=0.025

Hence,  the probability that a camera has a lens defect given that it has a charging defect is 0.025

You might be interested in
Solve and show all work |2×+3| -6=11​
mash [69]

Answer:

x = -10; x = 7  

Step-by-step explanation:

|2x + 3| - 6 =11

Add 6 to each side.

|2x + 3| = 17

Apply the absolute rule: If |x| = a, then x = a or x = -a.

(1) 2x + 3 = 17                    (2) 2x + 3 = -17

Subtract 3 from each side

         2x = 14                                 2x = -20

Divide each side by 2

          x = 7                                   x = -10

<em>Check: </em>

(1) |2(7) + 3| - 6 = 11                     (2) |2(-10) + 3| - 6 = 11

      |14 + 3| - 6 = 11                              |-20 + 3| - 6 = 11

             |17| - 6 = 11                                     |-17| - 6 = 1 1

              17 - 6 = 11                                        17 - 6 = 11

                    11 = 11                                              11 = 11

7 0
3 years ago
Hey! please help i’ll give brainliest
V125BC [204]

Answer:

The answer is D

Step-by-step explanation:

If and Then are italicized

3 0
2 years ago
Average of 766 and 878
Greeley [361]
(766+878)÷2=1644÷2=822
7 0
3 years ago
Kaitlin collected donations for a local animal shelter. She collected a total of $11 on Friday. She collected 7 times that amoun
qwelly [4]

Answer:

$77

Step-by-step explanation:

Let Friday be the variable f.

Let Saturday be the variable s.

f=11 \\ 7f=s

Substitute 11 for f in the second equation.

s=7(11) \\ s=77

Therefore, Kaitlin collected $77 on Saturday

4 0
3 years ago
Read 2 more answers
I don't know how to solve this :/
Dmitry_Shevchenko [17]
Multiply by 122. Thats your answer. Hope this helps
7 0
3 years ago
Other questions:
  • Carey needs $45 to buy her mother a gift. She has saved 22% of that amount so far. How much more money does she need?
    6·2 answers
  • When playing roulette at the Venetian casino in Las Vegas, a gambler is trying to decide whether to bet $5 on the number 27 or t
    13·1 answer
  • I’m not sure how to solve this. Please show how you solve this problem, thank you.
    11·1 answer
  • 8y - 1-/2 ( 4y - 16)
    13·1 answer
  • Ano ang dapat tandaan sa pagbuo ng plano ng proyekto​
    15·1 answer
  • Use these data to find the measures of center.
    12·1 answer
  • Please help I’ll give 40 extra points!!!
    14·2 answers
  • Find the surface area of the Triangular prism.<br><br> A = bh<br><br> A = 1/2(bh)
    10·1 answer
  • PLS HELP!! In a class of 30 students, the height of all students was measured and assembled in the table below. Find the value o
    11·1 answer
  • Two angles in triangle PQR are congruent, ∠P and ∠Q; ∠R measures 28.45°. What is the measure of ∠P?
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!