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ella [17]
3 years ago
6

The scale factor of the dimensions of two similar wood floors is 4:3. It costs $207 to refinish the smaller wood floor. At that

rate, how much would it cost to refinish the larger wood floor? $​
Mathematics
1 answer:
Crank3 years ago
6 0

Answer:

$276

Step-by-step explanation:

Create a proportion where x is the cost to refinish the larger wood floor:

\frac{4}{3} = \frac{x}{207}

Cross multiply and solve for x:

3x = 828

x = 276

So, to refinish the larger wood floor, it would cost $276

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Use I = PRT to solve. (time in years)
vivado [14]

Simple interest is $ 9

<em><u>Solution:</u></em>

Given that,

P = $ 400

R = 9 \% = \frac{9}{100} = 0.09

T = 0.25 years

<em><u>The formula for simple interest is:</u></em>

I = P \times R \times T

Where,

I is the simple interest earned

R is the rate of interest in decimal

T is the number of years

<em><u>Substituting the values we get,</u></em>

I = 400 \times 0.09 \times 0.25\\\\I = 36 \times 0.25\\\\I = 9

Thus simple interest is $ 9

8 0
3 years ago
Help me please it’s a test. question 15.
mr_godi [17]
I think 128????? my best guess
8 0
3 years ago
How do I subtract a whole number from a fraction
jasenka [17]

Answer:

In order to subtract a whole number from a fraction, you first have to turn the hole number into a mixed fraction.

Step-by-step explanation:

Say your fraction was 2/3 and your whole number was 5.

They have to have like denominators

5/1 - 2/3 = 15/3 - 2/3

15/3 - 2/3 = 13/3

13/3 = 4 1/3

6 0
3 years ago
A particular number was divided by 6 qnd then 5 was taken away from the quotient. Finally, the difference was mutiplird by 2. Gi
Nitella [24]
N is the number
divided by 6 then n/6
5 was taken away so (n/6)-5
the result is multiplied by 2 so 2((n/6)-5)
result is -12

-12=2((n/6)-5)
divide both sides by 2
-6=(n/6)-5
add 5
-1=n/6
times 6
-6=n
da number was -6
6 0
3 years ago
(7-13x^3-11x)-(2x^3+8-4x^5)
riadik2000 [5.3K]

Answer:

4x^5−15x^3−11x−1

Step-by-step explanation:

Simplify the expression. 4x^5−15x^3−11x−1

5 0
3 years ago
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