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EastWind [94]
2 years ago
5

An eight grader has 18 coins in her pocket. The coins are all dimes and quarters. Their total value is 2.85. Find how much of ea

ch coin is in her pocket.
Mathematics
1 answer:
Luda [366]2 years ago
7 0

Answer:

1 dimes and 9 quarters

Step-by-step explanation:

9 quarters = 2.75

1 dime = 10c

all together equals 2.85

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What is the answer a or b to this question
galina1969 [7]
The answer would be A.

Explanation:

If they enter with one car, that’s a price of $3 for the car alone. Because there’s also a fee for each person who enters, and there is a family of 5 who enters, x is representative of the cost for each person who enters. Therefore, there would be 5 x’s and one 3 that when solved would add up to the total of $45 they spent. That would mean A is correct because the equation would be x + x + x + x + x + 3 = 45.
5 0
1 year ago
The equation f = v + at represents the final velocity of an object, f, with an initial velocity, v, and an acceleration rate,
Veronika [31]
Um not to sure about that
7 0
3 years ago
Solve: 3n - 6 = -8(6 +5n)<br> and explain how to solve it
hjlf

Answer:

Step-by-step explanation:

First use distributive property: a(b + c) = a*b + a*c

3n - 6 = -8(6 + 5n)

3n - 6 = 6 * (-8) + 5n *(-8)

3n - 6 = -48 - 40n

Now add 40n to both sides

3n - 6 + 40n = -48 - 40n + 40n

43n - 6 = -48

Now add 6 to both sides

43n - 6 + 6 = -48 + 6

           43n = -42

               n = -42 /43

4 0
3 years ago
Read 2 more answers
What is the solution of 3/x+8 = -4?<br> 20
Evgen [1.6K]

Answer:

x = -1/4

Step-by-step explanation:

3/x = -4 - 8

3/x = -12

x= -3/12

x= -1/4

5 0
3 years ago
For a school fundraiser students are selling snack bags and candy bars to raise money on Wednesday the students or 23 snack bags
meriva

Answer:

$1.75

Step-by-step explanation:

The selling for each candy bar may be determined by  a set of linear equations. This pair of linear equations may be solved simultaneously by using the elimination method. This will involve ensuring that the coefficient of one of the unknown variables is the same in both equations.

It may be solved by substitution in that one of the variable is made the subject of the equation and the result is substituted into the second equation .

Let the cost of a snack bag be s and that of a candy bar be c, then if on Wednesday the students or 23 snack bags and 36 candy bars that raised $114.75 on Thursday the seventh so 37 snack bags and 36 candy bars that raised $146.25

23s + 36c = 114.75

37s + 36c = 146.25

14s = 31.5

s = $2.25

23(2.25) + 36c = 114.75

36c = 114.75 - 51.75

36c = 63

c = 63/36

= $1.75

3 0
3 years ago
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