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dalvyx [7]
3 years ago
13

Which of these would you most likely find on a ruler using the metric system? A. Centimeters B. Kilometers C. Kilofeet D. Microm

eters
Mathematics
1 answer:
maria [59]3 years ago
4 0

A. Centimeters

it's the one that isn't inches

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Please help asap for a math test
Kruka [31]

Answer:

negative    

positive

negative

positive

Step-by-step explanation:

-0.25

1/10

-0.2

1/2

5 0
2 years ago
What is 5 over 3 to the -2 power
dybincka [34]
Five over there to the power of negative two is
Three squared over five squared
Which is 9 over 25
6 0
3 years ago
Daisy measured the heights of 20 plants.
sergiy2304 [10]

Answer:

  • 30.5 cm

Step-by-step explanation:

<em>Refer to attached</em>

  • Height of plants (h) >> Frequency >> Midpoint >> Frequency x midpoint
  • 0 <h < 10 >>  1  >> 5 >> 5
  • 10 <h < 20 >> 4 >> 15 >>  60
  • 20 <h < 30 >> 7 >> 25 >> 175
  • 30 <h < 40 >> 2 >> 35 >> 70
  • 40 <h < 50 >> 3 >> 45 >> 135
  • 50 <h < 60 >> 3 >> 55 >> 165

Sum of frequencies = 20

Sum of frequency x midpoint product = 610

<u>Mean height </u>

  • 610/20 = 30.5 cm

5 0
3 years ago
Pla help pls : What is the first step to solving the following equation?<br> 5x – 11 = 42
kow [346]

Answer:

x = 10.6

Step-by-step explanation:

5x - 11 = 42

first +11 so,

5x = 53

then ÷5

x = 10.6

3 0
3 years ago
PLEASE HELP!!
PSYCHO15rus [73]

<u><em>Answer:</em></u>

The bird is approximately 9 ft high up in the tree

<u><em>Explanation:</em></u>

The required diagram is shown in the attached image

Note that the tree, the cat and the ground form a right-angled triangle

<u>Therefore, we can apply special trigonometric functions</u>

<u>These functions are as follows:</u>

sin(\alpha)=\frac{opposite}{hypotenuse} \\ \\ cos(\alpha)=\frac{adjacent}{hypotenuse} \\ \\tan(\alpha)=\frac{opposite}{adjacent}

<u>Now, taking a look at our diagram, we can note the following:</u>

α = 25°

The opposite side is the required height (x)

The adjacent side is the distance between the cat and the tree = 20 ft

Therefore, we can use the <u>tan function</u>

<u>This is done as follows:</u>

tan(\alpha)=\frac{opposite}{adjacent}\\ \\ tan(25)=\frac{x}{20}\\ \\x=20tan(25) = 9. 32 ft which is 9 ft approximated to the nearest ft

Hope this helps :)

5 0
3 years ago
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