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Trava [24]
3 years ago
5

Jack bought 4 bagels for 3.00. how many bagels can he buy for 4.50?

Mathematics
2 answers:
bija089 [108]3 years ago
6 0

Answer:

The answer is

<h2>6 bagels</h2>

Step-by-step explanation:

In order to solve this problem we use ratio and proportion

From the question

He used 3.00 to buy 4 bagels

Then 4.50 will be

\frac{4.5 \times 4}{3}  \\  =  \frac{18}{3}

We have the final answer as

<h3>6 bagels</h3>

Hope this helps you

romanna [79]3 years ago
5 0
He can buy six




Explanation :

Find the unit price of one bagel which is
3.00 divided by 4 and you get 0.75
4.50 divided by 0.75 is 6
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expeople1 [14]

Answer:

The answer to your question is:

Step-by-step explanation:

Q1. They are vertical angles, so they measure the same

                         

                           [2(x + 10)] = (3x - 30)

                           2x + 20 = 3x -30

                           2x - 3x = -30 - 20

                           - x = - 50

                             x = 50

Q2. They are also vertical angles, so they measure the same.

                          [6(x - 2)] = 3x + 30

                           6x - 12 = 3x + 30

                           6x - 3x = 30 + 12

                           3x = 42

                           x = 42/3

                           x = 14

∠DHG = 6(14 - 2)

∠DHG = 6(12)

∠DHG = 72

3 0
3 years ago
(1873-9y2+x-21) = (3x-4)
alex41 [277]

Answer:x= −9 /2 y^2+928

Step-by-step explanation:

6 0
3 years ago
For which x is f(x)=-3?<br> -7<br> -4<br> 4<br> 5
valina [46]
It is going to be (-7)
7 0
2 years ago
If 32x+1 - 3x+5, what is the value of x?<br> оооо
Zolol [24]

Answer:

x = \frac{4}{35}

Step-by-step explanation:

Given

32x + 1 = - 3x + 5 ( add 3x to both sides )

35x + 1 = 5 ( subtract 1 from both sides )

35x = 4 ( divide both sides by 35 )

x = \frac{4}{35}

7 0
3 years ago
Read 2 more answers
If y= 3x + 6, what is the minimum value of (x^3)(y)?
Rainbow [258]

Answer:

Given the statement: if y =3x+6.

Find the minimum value of (x^3)(y)

Let f(x) = (x^3)(y)

Substitute the value of y ;

f(x)=(x^3)(3x+6)

Distribute the terms;

f(x)= 3x^4 + 6x^3

The derivative value of f(x) with respect to x.

\frac{df}{dx} =\frac{d}{dx}(3x^4+6x^3)

Using \frac{d}{dx}(x^n) = nx^{n-1}

we have;

\frac{df}{dx} =(12x^3+18x^2)

Set \frac{df}{dx} = 0

then;

(12x^3+18x^2) =0

6x^2(2x + 3) = 0

By zero product property;

6x^2=0   and 2x + 3 = 0

⇒ x=0 and x = -\frac{3}{2} = -1.5

then;

at x = 0

f(0) = 0

and  

x = -1.5

f(-1.5) = 3(-1.5)^4 + 6(-1.5)^3 = 15.1875-20.25 = -5.0625


Hence the minimum value of (x^3)(y) is, -5.0625






3 0
3 years ago
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