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3 years ago

Jack bought 4 bagels for 3.00. how many bagels can he buy for 4.50?

Mathematics

2 answers:

bija089 [108]3 years ago

6 0

Answer:

The answer is

<h2>6 bagels</h2>

Step-by-step explanation:

In order to solve this problem we use ratio and proportion

From the question

He used 3.00 to buy 4 bagels

Then 4.50 will be

$\frac{4.5 \times 4}{3} \\ = \frac{18}{3}$

We have the final answer as

<h3>6 bagels</h3>

Hope this helps you

romanna [79]3 years ago

5 0

He can buy six

Explanation :

Find the unit price of one bagel which is
3.00 divided by 4 and you get 0.75
4.50 divided by 0.75 is 6

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Answer:

The answer to your question is:

Step-by-step explanation:

Q1. They are vertical angles, so they measure the same

[2(x + 10)] = (3x - 30)

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2x - 3x = -30 - 20

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x = 50

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[6(x - 2)] = 3x + 30

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x = 14

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3 years ago

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Step-by-step explanation:

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3 years ago

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valina [46]

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2 years ago

If 32x+1 - 3x+5, what is the value of x?<br> оооо

Zolol [24]

Answer:

x = $\frac{4}{35}$

Step-by-step explanation:

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Read 2 more answers

If y= 3x + 6, what is the minimum value of (x^3)(y)?

Rainbow [258]

Answer:

Given the statement: if y =3x+6.

Find the minimum value of $(x^3)(y)$

Let f(x) = $(x^3)(y)$

Substitute the value of y ;

$f(x)=(x^3)(3x+6)$

Distribute the terms;

$f(x)= 3x^4 + 6x^3$

The derivative value of f(x) with respect to x.

$\frac{df}{dx} =\frac{d}{dx}(3x^4+6x^3)$

Using $\frac{d}{dx}(x^n) = nx^{n-1}$

we have;

$\frac{df}{dx} =(12x^3+18x^2)$

Set $\frac{df}{dx} = 0$

then;

$(12x^3+18x^2) =0$

$6x^2(2x + 3) = 0$

By zero product property;

$6x^2=0$ and 2x + 3 = 0

⇒ x=0 and x = $-\frac{3}{2} = -1.5$

then;

at x = 0

f(0) = 0

and

x = -1.5

$f(-1.5) = 3(-1.5)^4 + 6(-1.5)^3 = 15.1875-20.25 = -5.0625$

Hence the minimum value of $(x^3)(y)$ is, -5.0625

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3 years ago