Ask question

Ask question

All categories

3 years ago

11

4. Solve the equation 3x + 2 = 17 using the bar diagram. 17 х х Х 2

1 answer:

Zinaida [17]3 years ago

5 0

:
5
:
3x+2=17
-2 -2
3x=15
/3 /3
x=5

You might be interested in

Question 2 (20 points)

almond37 [142]

The answer is:

7 miles

5+2=7

3 0

3 years ago

Read 2 more answers

enyata [817]

Answer:

(E) 90°

Step-by-step explanation:

The diagonals of a parallelogram are equal in length if and only if the parallelogram is a rectangle.

Any angle of a rectangle is 90°.

_____

Adjacent angles of a parallelogram are supplementary. If the diagonals are the same length, the triangles formed by either diagonal are congruent with the triangles formed by the other diagonal. This means adjacent angles are congruent. Congruent supplementary angles are 90°.

7 0

2 years ago

Help please!!!!!!!!!!!

andreev551 [17]

Answer:

download a app called photo math

Step-by-step explanation:

Thank me later

3 0

2 years ago

A cash box contains $74 made up of quarters, half-dollars, and one-dollar

Strike441 [17]

Answer:

25 one-dollar coins, 16 half-dollar coins, and 164 quarters

Step-by-step explanation:

First, set up equations based on the information given:

$0.25q+0.50h+1.00d=74$

$\displaystyle{h=\frac{3}{5}d+1}$

$q=4(d+h)$

Then, substitute <em>q</em> in the first equation with the expression from the third equation:

$0.25[4(d+h)]+0.50h+1.00d=74\\1d+1h+0.50h+1.00d=74\\2d+1.5h=74$

Next, substitute <em>h</em> in that equation with the expression from the second equation:

$\displaystyle{2d+1.5(\frac{3}{5}d+1)=74}$

$2d+0.9d+1.5=74\\2.9d+1.5=74$

Solve for <em>d</em>, the number of one-dollar coins:

$2.9d+1.5=74\\2.9d=72.5\\d=25$

Substitute 25 for <em>d</em> in the second equation to find <em>h</em>, the number of half-dollar coins:

$\displaystyle{h=\frac{3}{5}d+1}$

$\displaystyle{h=\frac{3}{5}(25)+1}$

$h=15+1\\h=16$

Substitute 25 for <em>d</em> and 16 for <em>h</em> in the third equation to find <em>q</em>, the number of quarters:

$q=4(d+h)\\q=4(25+16)\\q=4(41)\\q=164$

Then, verify that the coins total $74:

$0.25(164)+0.50(16)+1.00(25)=74\\41+8+25=74\\74=74\\\text{Check.}$

Next, verify that the number of half-dollar coins is one more than three-fifths of the number of one-dollar coins:

$\displaystyle{h=\frac{3}{5}d+1}$

$\displaystyle{16=\frac{3}{5}(25)+1}$

$16 = 15 + 1\\16 = 16\\\text{Check.}$

Finally, verify that the number of quarters is four times the number one-dollar and half-dollar coins together:

$q=4(d+h)\\164=4(25+16)\\164=4(41)\\164=164\\\text{Check.}$

6 0

3 years ago

Please help?!?!?!?! Thanks if you do

Fynjy0 [20]

The answer: F = 1.7 ml

7 0

3 years ago