4. Solve the equation 3x + 2 = 17 using the bar diagram.<br> 17<br> х<br> х<br> Х<br> 2

If you have 2 pounds of grapes and there $6 how much is 1 pound grapes?

Vikki [24]

Answer:

$3

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

[please help asap!]

Citrus2011 [14]

Answer:

(a+b)^2 = a^2 + 2ab + b^2

(a-b)^2 = a^2 - 2ab + b^2

(a-b)(a+b) = a^2 - b^2

Step-by-step explanation:

They differ because you can either add the property or multiply

5 0

3 years ago

For every 5 pages Gill can read his daughter can read 3 pages

Free_Kalibri [48]

Answer:

Explain your answer that's no answer if looking for a ratio of5:3 but there aren't choices to choose from

Step-by-step explanation:

5 0

3 years ago

From the equations below, which one is another example of an equation with

Alenkinab [10]

Answer:

last one

Step-by-step explanation:

the first one doesn't have any solution, the second one has infinite solutions.

8 0

3 years ago

About 7% of men in the United States have some form of red-green color blindness. Suppose we

Afina-wow [57]

Answer:

<h2>The probability will be $\frac{9538}{37345}$ </h2>

Step-by-step explanation:

<u>Let the total population of United States is 100.</u>

As per the given scenario, among them 7 men have the red-green color blindness.

Among the 4 selected males having at least 1 man having color blindness there could be total 4 possible cases.

CASE 1:

1 of the 4 men having blindness.

The probability will be $\frac{7C1\times93C3}{100C4} = \frac{7\times\frac{93\times92\times91}{6} }{\frac{100\times99\times98\times97}{24} } = \frac{28\times93\times92\times91}{100\times99\times98\times97}$

CASE 2:

2 of the 4 men having blindness.

The probability in this case will be $\frac{7C2\times93C2}{100C4} = \frac{7\times6\times\frac{93\times92}{2} }{\frac{100\times99\times98\times97}{24} } = \frac{56\times93\times92}{100\times99\times98\times97}$

CASE 3:

3 of the 4 men having blindness.

The required probability is $\frac{7C3\times93C1}{100C4} = \frac{7\times6\times\frac{93\times5}{6} }{\frac{100\times99\times98\times97}{24} } = \frac{35\times93\times24}{100\times99\times98\times97}$

CASE 4:

All of the 4 men that will be chosen, have the blindness.

In this case all of the men will be chosen from the 7% of the total population.

Hence, the probability is $\frac{7C4}{100C4} = \frac{7\times6\times5\times4 }{100\times99\times98\times97 } = \frac{35\times24}{100\times99\times98\times97}$

As any of the above 4 cases could be possible, in order to get the desired answer we need to add them.

hence, the answer is $\frac{9538}{37345}$

4 0

3 years ago

4. Solve the equation 3x + 2 = 17 using the bar diagram. 17 х х Х 2