Find the 38th term of the sequence. 359, 352, 345
1 answer:
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Given:
The quadratic equation is:
To find:
The solution for the given equation rounded to 2 decimal places.
Solution:
Quadratic formula: If a quadratic equation is , then:
We have,
Here, . Using the quadratic formula, we get
Now,
And
Therefore, the required solutions are 1.14 and -1.47.
12. 
r - 3 = 4(-5)
r - 3 = -20
r = -20 + 3
r = -17
13.
6(r - 2) = -7(5)
6r - 12 = -35
6r = -35 + 12
6r = - 23
r =
r - 3 = 4(-5)
r - 3 = -20
r = -20 + 3
r = -17
13.
6(r - 2) = -7(5)
6r - 12 = -35
6r = -35 + 12
6r = - 23
r =