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pantera1 [17]
2 years ago
5

Need answer ASAP. Worth 25 points

Mathematics
1 answer:
kompoz [17]2 years ago
5 0

I think the answer is B and C

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Which of the ordered pairs in the form (x, y) is a solution of this equation?
Tju [1.3M]

Answer:

Both ordered pairs are solutions to this equation.

Step-by-step explanation:

If you plug in the x and y values given in the ordered pair, you make the left side of the equation equal the right for both pairs.

6 0
3 years ago
Find the solution set
AVprozaik [17]
M1= -5 , m2 = 5 inorder to get this you move the constant to the right take the root of both sides separate the solutions and you should get m1= -5, m2 =5
7 0
3 years ago
Find the midpoint of the line using the midpoint formula.<br> Midpoint of AB:______
dimaraw [331]

Answer: MP=(1,1)

Step-by-step explanation:

MP= (\frac{x_1+x_2}{2})(\frac{y_1+y_2}{2})

MP= (\frac{-2+4}{2})(\frac{-3+5}{2}) -2+4=2  -3+5=2

MP= (\frac{2}{2})(\frac{2}{2}) 2/2=1

MP= (1,1)    

8 0
2 years ago
a stone falls from a ledge and takes 8 seconds to the hit the ground. the stone has an original velocity of 0 m/s. how tall is t
Verizon [17]
Using equation of motion.

S = ut + (1/2)gt²

Where S = Height, t = time, g = acceleration due to gravity = 9.8 m/s²

time, t = 8 seconds 

Since it was dropped from height, initial velocity, u = 0

S = 0*t + (1/2)gt²

S = (1/2)gt²

S = (1/2)*9.8*8²  = 4.9 * 8 * 8 =  313.6

Therefore the ledge is 313.6 m tall.
6 0
2 years ago
Read 2 more answers
Suppose the sample space for a probability experiment has 8 elements. If elements from the sample are selected without replaceme
Gwar [14]

Answer: Number of ways =\dfrac{8!}{8!0!}\ or \ 1

Step-by-step explanation:

When there is no replacement , we use combination to find the number of ways to choose things.

Number of ways to choose r things out of  ( with out replacement) = ^nC_r=\dfrac{n!}{r!(n-r)!}

The number of ways to choose  8 things = ^8C_8=\dfrac{8!}{8!(8-8)!}=\dfrac{1}{0!}=1  [\because 0!=1]

Hence,  Number of ways =\dfrac{8!}{8!0!}\ or \ 1

5 0
2 years ago
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