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3 years ago

Write m=-3 and (3,-1) in point slope form

Mathematics

1 answer:

Art [367]3 years ago

7 0

Answer:

(y+1)= -3(x-3)

Step-by-step explanation:

Use Point-Slope Formula

$(y-y_{1} )=m(x-x_{1} )$

Substitute

$(y+1) =-3(x-3)$

You might be interested in

Which of the following points is a solution of y > |x| + 5?

Morgarella [4.7K]

You can do this one simply just by plugging in the values of x and y for each answer.
Note: (0,5) is just a way to right x=0 and y=5

Try answer A (0,5)
$y\ \textgreater \ |x|+5$
$5\ \textgreater \ |0|+5$
$5\ \textgreater \ 0+5$
$5\ \textgreater \ 5$
This is not true. 5 is not bigger than 5 so A is not the answer

Try answer B (1,7)
$y\ \textgreater \ |x|+5$
$7\ \textgreater \ |1|+5$
$7\ \textgreater \ 1+5$
$7\ \textgreater \ 6$
This is true so answer B works!

Might as well try answer C (7,1)
$y\ \textgreater \ |x|+5$
$1\ \textgreater \ |7|+5$
$1\ \textgreater \ 7+5$
$1\ \textgreater \ 12$
1 is obviously not greater than 12 so C does not work

The answer is B (1,7)

5 0

3 years ago

Fernando has two equally-sized containers of clay which he is using to build a pyramid-like structure. The finished structure wi

evablogger [386]

Answer:

Fernando does not have enough clay to finish the structure since, the expressions for the volume left are not the same.

Step-by-step explanation:

Let w be the length of the longest slab. Since each slab is 2 inches less than the one beneath it, we have the width of the other 3 slabs as w - 2, w - 2 - 2 = w - 4 and w - 4 - 2 = w - 6 respectively.

Since the base of each slab is a square and has thickness 2 inches, the volume of each slab from largest to smallest is thus 2w², 2(w - 2)², 2(w - 4)² and 2(w - 6)² respectively.

We have that we have half of the container of clay left after forming the first two slabs(which are the bottom-most slabs). Let V be the volume of each clay container. Since we have half left, that is V/2, we have used 2V - V/2 = 3V/2 to make the two bottom-most slabs.

So, 3V/2 = 2w² + 2(w - 2)²

= 2w² + 2(w² - 4w + 4)

= 2w² + 2w² - 8w + 8

= 4w² - 8w + 8

= 4(w² - 2w + 2) (1)

Also we want to know if V/2 is equal to the volume of the two top-most slabs.

So, V/2 = 2(w - 4)² + 2(w - 6)²

= 2(w² - 8w + 16) + 2(w² - 12w + 36)

= 2w² - 16w + 32 + 2w² - 24w + 72

= 4w² - 40w + 104

= 4(w² - 10w + 26)

From (1) V/2 = 4(w² - 2w + 2)/3 ≠ 4(w² - 10w + 26)

Since the expressions for the remaining volume are not the same, Fernando does not have enough clay to finish the structure.

4 0

3 years ago

On a piece of paper use a protractor to construct a triangle with angle measures of 40 and 60 what is the measure of the third a

Lina20 [59]

Answer:

80°

Step-by-step explanation:

The angles of a triangle must add up to 180°.

40° + 60° + missing angle = 180°

100° + missing angle = 180°

subtract 100° from both sides

missing angle = 80°

7 0

3 years ago

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th

oksian1 [2.3K]

Answer:

17 seconds

Step-by-step explanation:

Solution:-

The trajectory of a rocket launched is modeled by a parabolic path via a quadratic equation as follows:

$y = -16x^2 + 266x +102$

Where,

y: The height of the rocket from ground

x: The time taken since rocket launch

We are to determine the time ( x ) it takes for the rocket to hit the ground. This can be determined by setting the quantity ( y ) to zero as follows

$y = -16x^2 + 266x +102 = 0\\\\ -16x^2 + 266x +102 = 0$

solve the quadratic equation using quadratic formula as follows:

$x = \frac{-b +/- \sqrt{b^2 - 4ac} }{2a} \\\\x = \frac{-266 +/- \sqrt{266^2 - 4*(-16)*(102)} }{2*(-16)} \\\\x = \frac{-266 +/- 278 }{-32} \\\\x = 8.3125 +/- 8.6875\\\\x = 17 , -0.375$

Answer: Ignore the negative value for time " -0.375 ". Hence, the rocket hits the ground at time t = 17 seconds

6 0

3 years ago

Which of the following correctly describes the symmetry of the cubic parent

inysia [295]

Answer:

Note: By definition, no function can be symmetric about the x-axis (or any ... B: the graph of an hyperbola ... C: the graph of a cubic ... Graph D: This cubic is centered at the point (0, –3).

7 0

3 years ago