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nevsk [136]
2 years ago
10

Chandler, Jamal, Allison, and Qi are given the following problem. In 1982, Wayne Gretsky set a record for the greatest number of

hockey goals in one season with 92 goals. If a player has scored 60 goals this season and averages 2 goals per game, how many additional games must he play to break the record? Each student writes an inequality to represent the situation. Chandler wrote 60 + 2g ≥ 92 Jamal wrote 60 + 2g > 92 Allison wrote 60 + 2g < 92 Qi wrote 60 + 2g ≤ 92 Whose inequality is CORRECT? A. Qi B. Chandler C. Allison D. Jamal
Mathematics
1 answer:
Pavel [41]2 years ago
6 0

Answer:

The correct answer is B.

Step-by-step explanation:

Since Chandler, Jamal, Allison, and Qi are given the following problem: "In 1982, Wayne Gretsky set a record for the greatest number of hockey goals in one season with 92 goals. If a player has scored 60 goals this season and averages 2 goals per game, how many additional games must he play to break the record? ", And each student writes an inequality to represent the situation:

Chandler wrote 60 + 2g ≥ 92

Jamal wrote 60 + 2g> 92

Allison wrote 60 + 2g <92

Qi wrote 60 + 2g ≤ 92

To determine whose inequality is correct, the following calculation must be performed:

92 - 60 = 32

32/2 = 16

Chandler: 60 + 2x16 ≥ 92

Thus, Chandler wrote the correct option.

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Step-by-step explanation:

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3 years ago
The denominator of a fraction is 4 more than the numerator if both are decreased by 3 the simplified result is 6/7 find original
Hitman42 [59]

<u>Answer:</u>

The denominator of a fraction is 4 more than the numerator. The original fraction is \frac{27}{31}

<u>Solution:</u>

Given that  

Denominator of fraction is 4 more than the numerator.

Let’s say numerator of fraction be represented by variable x.

So denominator of a faction as it is four more that numerator will be x + 4

Also given if both decreased by three than simplified result is \frac{6}{7}

=>\frac{(x-3)}{((x+4)-3)}=\frac{6}{7}

Solving above equation for x

=> 7(x – 3  ) = 6 ( x + 1 )

=> 7x – 21 = 6x + 6

=> 7x – 6x = 6 + 21

=> x = 27

Numerator of fraction = x = 27

Denominator of fraction = x + 4 = 27 + 4 = 31

\text {required fraction}=\frac{\text {numerator}}{\text {denominator}}

= \frac{27}{31}

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