Let the number be x,
(1/2)x=1+(1/3)x
Solving for x,
(1/2)x-(1/3)x=1+(1/3)x-(1/3)x
(1/2)x-(1/3)x=1
(1*3/6)x-(1*2/6)x=1
(3/6)x-(2/6)x=1
(1/6)x=1
6*(1/6)x=6*1
Therefore, x=6
We want to solve the Initial Value Problem y' = y + 4xy, with y(0) = 1.
To use Euler's method, define
y(i+1) = y(i) + hy'(i), for i=0,1,2, ...,
where
h = 0.1, the step size.,
x(i) = i*h
1st step.
y(0) = 1 (given) and x(0) = 0.
y(1) ≡ y(0.1) = y(0) + h*[4*x(0)*y(0)] = 1
2nd step.
x(1) = 0.1
y(2) ≡ y(0.2) = y(1) + h*[4*x(1)*y(1)] = 1 + 0.1*(4*0.1*1) = 1.04
3rd step.
x(2) = 0.2
y(3) ≡ y(0.3) = y(2) + h*[4*x(2)*y(2)] = 1.04 + 0.1*(4*0.2*1.04) = 1.1232
4th step.
x(3) = 0.3
y(4) ≡ y(0.4) = y(3) + h*[4*x(3)*y(3)] = 1.1232 + 0.1*(4*0.3*1.1232) = 1.258
5th step.
x(4) = 0.4
y(5) ≡ y(0.5) = y(4) + h*[4*x(4)*y(4)] = 1.258 + 0.1*(4*0.4*1.258) = 1.4593
Answer: y(0.5) = 1.4593
Answer:
it would be 90 degrees clocwise
Answer: 10
Step-by-step explanation: d = √(x^²-x^₁)^2+(y^²-y^₁)^2 d = √ (-3-5)^2+ (-5-1)^2 d = √(-8)^2 + (-6)^2 d = √64+36 d = √100 d = 10
They are the same because if you add a zero it doesnt change it
