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Evgesh-ka [11]
2 years ago
8

Which strategy would most help minimize the risk of being underinsured

Mathematics
2 answers:
kvv77 [185]2 years ago
7 0

Answer: choosing the maximum coverage

Step-by-step explanation:

Tcecarenko [31]2 years ago
3 0

Choosing the maximum coverage

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A die is tossed two times and the number appearing on the die is noted each time. What is the probability that the sum of two nu
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Answer: 99

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Answer the following questions: 2/3 is what percent of 1/4?
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Answer:

1/2 or 0.5

Step-by-step explanation:

To find out what 2/3 is out of 3/4, we just have to multiply them together to get our exact answer.

\frac{2}{3} *\frac{3}{4}=\frac{6}{12}=\frac{1}{2}

Our final answer is 1/2 or 0.5.

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Omar's credit card has an APR of 26% calculated on the previous monthly balance
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$257.33 on Apex  it’s correct, I took the quiz


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You are studying for your final exam of the semester. up to this point,you recieved 3 exam scores of 76%,99%, and 86%. to reciev
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A local company is concerned about the number of days missed by its employees due to ill ness. A Random Sample of 10 employees i
sukhopar [10]

Answer:

The incentive program does not cuts down on the number of days missed by employees.

Step-by-step explanation:

The dependent t-test (also known as the paired t-test or paired samples t-test) compares the two means associated groups to conclude if there is a statistically significant difference amid these two means.

A paired <em>t</em>-test would be used to determine whether the incentive program cuts down on the number of days missed by employees.

The hypothesis for the test can be defined as follows:

<em>H₀</em>: The incentive program does not cuts down on the number of days missed by employees, i.e. <em>d</em> ≥ 0.

<em>Hₐ</em>: The incentive program cuts down on the number of days missed by employees, i.e. <em>d</em> < 0.

From the information provided the data computed is as follows:

 n=10\\\bar d=-1.1\\SD_{d}=2.99

Compute the test statistic value as follows:

 t=\frac{\bar d}{SD_{d}/\sqrt{n}}

   =\frac{-1.1}{2.99/\sqrt{10}}\\\\=-1.16

The test statistic value is -1.16.

Decision rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.

Compute the p-value of the test as follows:

p-value=P(t_{n-1}

*Use a t-table.

The p-value of the test is 0.1379.

The p-value of the test is very large for all the commonly used significance level. The null hypothesis will not be rejected.

Thus, there is not enough evidence to support the claim.

Conclusion:

The incentive program does not cuts down on the number of days missed by employees

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