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vladimir1956 [14]
3 years ago
12

If df=78, de=5x-9, and ef=2x+10, find ef

Mathematics
1 answer:
9966 [12]3 years ago
4 0
As e is point between df. So we can write df as 
df = de + ef

As given df = 78 , de = 5x - 9 , ef = 2x + 10.

So we can write

78 = 5x - 9 + 2x + 10

78 = 7x + 1

On subtracting 1 on booth side

78 - 1 = 7x +1 - 1

77 = 7x

On dividing both side by 7.

\frac{77}{7} =  \frac{7x}{7}

11 = x

So x = 11.

So ef = 2x + 10 = 2*11 + 10 = 22 + 10 = 32
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