Answer:
The image will be congruent to ΔMNP.
Line EG will be perpendicular to the line segments connecting the corresponding vertices.
The line segments connecting corresponding vertices will all be parallel to each other.
Step-by-step explanation:
The reflected image will be the mirror image of ΔMNP, so it will be congruent. The lines connecting each vertex to the corresponding vertex will be parallel, and all three lines are perpendicular to EG.
4, 5, 3, 3, 1, 2, 3, 2, 4, 8, 2, 4, 4, 5, 2, 3, 6,2
Anna007 [38]
Answer:
<u>Given data:</u>
- 4, 5, 3, 3, 1, 2, 3, 2, 4, 8, 2, 4, 4, 5, 2, 3, 6,2
<u>Put the data in the ascending order:</u>
- 1, 2, 2, 2, 2, 2, 3, 3, 3, 3, 4, 4, 4, 4, 5, 5, 6, 8
<u>Mean, the average:</u>
- (1 + 2*5 + 3*4 + 4*4 + 5*2 + 6 + 8)/18 = 3.5
<u>Median, average of middle two numbers:</u>
<u>Mode, the most repeated number:</u>
Mean is normally the best measure of central tendency, same applies to this data.
The correct answer is 'Equation F can be written as 2d + 1 = 3d + 7'. In order to find the answer to a system of equations, the two equations must be set equal to each other. For instance, if we had the equations x = y + 1 and x = 3y - 1, we would set the two equations equal to one another to find the answer.
x = y + 1
x = 3y - 1
y + 1 = 3y - 1
1 = 2y - 1
2 = 2y
1 = y
x = y + 1
x = 1 + 1
<span>x = 2
We can use this to solve the set of equations above.
</span><span>2d + 1 = 3d + 7
</span>1 = d + 7
-6 = d
c = 2d + 1
c = 2(-6) + 1
c = -12 + 1
c = -11
Hope this helps!
3.) An extreme value refers to a point on the graph that is possibly a maximum or minimum. At these points, the instantaneous rate of change (slope) of the graph is 0 because the line tangent to the point is horizontal. We can find the rate of change by taking the derivative of the function.
y' = 2ax + b
Now that we where the derivative, we can set it equal to 0.
2ax + b = 0
We also know that at the extreme value, x = -1/2. We can plug that in as well.
The 2 and one-half cancel each other out.
Now we know that a and b are the same number, and that ax^2 + bx + 10 = 0 at x = -1/2. So let's plug -1/2 in for x in the original function, and solve for a/b.
a(-0.5)^2 + a(-0.5) + 10 = 0
0.25a - 0.5a + 10 = 0
-0.25a = -10
a = 40
b = 40
To determine if the extrema is a minima or maxima, we need to go back to the derivative and plug in a/b.
80x + 40
Our critical number is x = -1/2. We need to plug a number that is less than -1/2 and a number that is greater than -1/2 into the derivative.
LESS THAN:
80(-1) + 40 = -40
GREATER THAN:
80(0) + 40 = 40
The rate of change of the graph changes from negative to positive at x = -1/2, therefore the extreme value is a minimum.
4.) If the quadratic function is symmetrical about x = 3, that means that the minimum or maximum must be at x = 3.
y' = 2ax + 1
2a(3) + 1 = 0
6a = -1
a = -1/6
So now plug the a value and x=3 into the original function to find the extreme value.
(-1/6)(3)^2 + 3 + 3 = 4.5
The extreme value is 4.5
Step-by-step explanation:
5(2h+8) <60
10h +40< 60
10h + 40-40 < 60-40
10h < 20
10h/10 < 20/10
h < 2
