Question

NEED HELP ASAP WILL MARK BRAINLIEST!

Answer 1

Answer:

log_{b} (5b) = 2.609

Given that:

log_{b} (3) = 1.099

log_{b} (5) = 1.609

Evaluating with that:

$\sf log_b (5b) = log_b\left(5\right)+log_b\left(b\right)$

            $= \sf 1.609 + 1$

             $= \sf 2.609$

Rule Used:

$\rm \log _a\left(xy\right)=\log _a\left(x\right)+\log _a\left(y\right)$