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Likurg_2 [28]
3 years ago
10

Ctimes%20%5C%3A%20%5Cdfrac%7B7.5%7D%7B12%7D%7D%7D" id="TexFormula1" title="\sf{\longrightarrow{20000 \: \times \: \dfrac{9}{100} \times \: \dfrac{7.5}{12}}}" alt="\sf{\longrightarrow{20000 \: \times \: \dfrac{9}{100} \times \: \dfrac{7.5}{12}}}" align="absmiddle" class="latex-formula">
​
Mathematics
2 answers:
Licemer1 [7]3 years ago
5 0

Answer:

Correcr answer is 1125. See picture.

frutty [35]3 years ago
3 0

\sf{\longrightarrow20000 \times  \frac{9}{100}  \times  \frac{7.5}{12}}

\sf{\longrightarrow200 \: \times 9 \times  \frac{7.5}{12}}

\sf{\longrightarrow200 \times 3 \times  \frac{7.5}{4}}

\sf{\longrightarrow50 \times 3  \times 7.5}

\sf{\longrightarrow50 \times 22.5}

{\longrightarrow\large\boxed{\sf1125.}}

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What is the best estimate for this sum 1/8+1/6=The sum will be close to?
tamaranim1 [39]

The expression given is

\frac{1}{8}+\frac{1}{6}

The sum of the expression will be,

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The sum will be

\frac{7}{24}

8 0
1 year ago
Steve's scores on 6 of his tests were 92, 78, 86, 92, 95, and 91. If he took a seventh test and raised the mean of his scores by
monitta

Answer:

96

Step-by-step explanation:

First we need to know the mean of the Steve's scores on 6 of his tests. Given the six scores as 92, 78, 86, 92, 95, and 91.

Mean = sum of the scores/Total test taken

Mean = 92+78+86+92+95+ 91/6

Mean = 534/6

Mean = 89

If he took the seventh test and the mean score is raised by 1 them the new mean will be expressed as;

New mean = 92+78+86+92+95+ 91+x/7 = 89+1

Where x is the new score. Note that of a new score is added, the total year taken will also change to 7

To get x;

92+78+86+92+95+ 91+x/7 = 89+1

92+78+86+92+95+ 91+x/7 = 90

534+x/7 = 90

Cross multiply

533+x = 90×7

533+x = 630

x = 630-534

x = 96

Hence the score of the seventh test is 96

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