Answer:
Sheridan's Work is correct
Step-by-step explanation:
we know that
The lengths side of a right triangle must satisfy the Pythagoras Theorem
![c^{2}=a^{2}+b^{2}](https://tex.z-dn.net/?f=c%5E%7B2%7D%3Da%5E%7B2%7D%2Bb%5E%7B2%7D)
where
a and b are the legs
c is the hypotenuse (the greater side)
In this problem
Let
![a=7\ cm\\c=13\ cm](https://tex.z-dn.net/?f=a%3D7%5C%20cm%5C%5Cc%3D13%5C%20cm)
substitute
![13^{2}=7^{2}+b^{2}](https://tex.z-dn.net/?f=13%5E%7B2%7D%3D7%5E%7B2%7D%2Bb%5E%7B2%7D)
Solve for b
![169=49+b^{2}](https://tex.z-dn.net/?f=169%3D49%2Bb%5E%7B2%7D)
![b^{2}=169-49](https://tex.z-dn.net/?f=b%5E%7B2%7D%3D169-49)
![b^{2}=120](https://tex.z-dn.net/?f=b%5E%7B2%7D%3D120)
![b=\sqrt{120}\ cm](https://tex.z-dn.net/?f=b%3D%5Csqrt%7B120%7D%5C%20cm)
![b=10.95\ cm](https://tex.z-dn.net/?f=b%3D10.95%5C%20cm)
we have that
<em>Jayden's Work</em>
![a^{2}+b^{2}=c^{2}](https://tex.z-dn.net/?f=a%5E%7B2%7D%2Bb%5E%7B2%7D%3Dc%5E%7B2%7D)
![a=7\ cm\\b=13\ cm](https://tex.z-dn.net/?f=a%3D7%5C%20cm%5C%5Cb%3D13%5C%20cm)
substitute and solve for c
![7^{2}+13^{2}=c^{2}](https://tex.z-dn.net/?f=7%5E%7B2%7D%2B13%5E%7B2%7D%3Dc%5E%7B2%7D)
![49+169=c^{2}](https://tex.z-dn.net/?f=49%2B169%3Dc%5E%7B2%7D)
![218=c^{2}](https://tex.z-dn.net/?f=218%3Dc%5E%7B2%7D)
![c=\sqrt{218}\ cm](https://tex.z-dn.net/?f=c%3D%5Csqrt%7B218%7D%5C%20cm)
![c=14.76\ cm](https://tex.z-dn.net/?f=c%3D14.76%5C%20cm)
Jayden's Work is incorrect, because the missing side is not the hypotenuse of the right triangle
<em>Sheridan's Work</em>
![a^{2}+b^{2}=c^{2}](https://tex.z-dn.net/?f=a%5E%7B2%7D%2Bb%5E%7B2%7D%3Dc%5E%7B2%7D)
![a=7\ cm\\c=13\ cm](https://tex.z-dn.net/?f=a%3D7%5C%20cm%5C%5Cc%3D13%5C%20cm)
substitute
![7^{2}+b^{2}=13^{2}](https://tex.z-dn.net/?f=7%5E%7B2%7D%2Bb%5E%7B2%7D%3D13%5E%7B2%7D)
Solve for b
![49+b^{2}=169](https://tex.z-dn.net/?f=49%2Bb%5E%7B2%7D%3D169)
![b^{2}=169-49](https://tex.z-dn.net/?f=b%5E%7B2%7D%3D169-49)
![b^{2}=120](https://tex.z-dn.net/?f=b%5E%7B2%7D%3D120)
![b=\sqrt{120}\ cm](https://tex.z-dn.net/?f=b%3D%5Csqrt%7B120%7D%5C%20cm)
![b=10.95\ cm](https://tex.z-dn.net/?f=b%3D10.95%5C%20cm)
therefore
Sheridan's Work is correct
Answer: If you mean five instead of time, then the answer would be 82.5
Step-by-step explanation:
15 × 5.5 = 82.5
Answer:
c = 13.52 units.
Step-by-step explanation:
So for this, lets use the Law of Sines, which says that:
Sin A / a = Sin B / b = Sin C / c
We have everything for this except the the angle measure of angle C. This can be found by doing 180 - 80 - 33, since the total interior angle measure of a triangle always equals 180 degrees.
180 - 80 - 33 = 67 degrees
With this, we can use the angle & side of A/a as well as the angle of C to get the side of c by using the Law of Sines
Sin A / a = Sin C / c
sin 33/8 = sin 67/c
c = 8*sin67 / sin 33
c = 13.52 units.
Answer:
46 mph and 61 mph
Step-by-step explanation:
Distance=speed*time
Let speed of one bus be x and another x+15
After 3 hours
First bus would have traveled 3x while second bus 3(x+15)=3x+45
Total distance= 3x+3x+45=6x+45
6x+45=321
6x=321-45=276
x=276/6=46 mph
x+15=46+15=61 mph
Answer: One solution
Step-by-step explanation:
y = 3x + 3
y = -2x + 3
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To solve this, you need to understand a few things:
a) If two lines have the same slope but different y-intercepts, they are parallel when graphed and thus do not have any solutions
b) If two lines have the same slope and same y-intercepts, they are the same line when graphed and thus do not have infinitely many solutions
c) If two lines have different slopes (and/or y-intercepts), they have one solution
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These two lines have different slopes but the same y-intercept (condition c)
So they have one solution