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never [62]
3 years ago
15

Find the value of y.

Mathematics
1 answer:
daser333 [38]3 years ago
5 0

Answer:

no clue

Step-by-step explanation:

idk how to do that

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zysi [14]
Photomath is the best for fractions, decimals ect. You could also try a scientific calculator.
5 0
3 years ago
Consider the function y=x^2+5x-2 . What would happen to the graph if (x -1) was substituted in place of the x?
Ilia_Sergeevich [38]

Answer:

B.

Step-by-step explanation:

f(x - c) shift the function <em>c</em> units to the right.

In this case, if (x - 1) was substituted in place of the x, the graph would shift 1 unit to the right.

If you want to graph the new function and know the graph of the previous one, this relationship avoids you the substitution of (x - 1) into the function and expansion of the expression to obtain a new quadratic formula.

3 0
3 years ago
How do you know if a whole number is a perfect square
kirill [66]

Answer:

you simply think of a number that when multiplied by itself it will give you that whole number

Step-by-step explanation:

let's take for instance the number 4 it's a whole number and still a perfect square because when you think of a number from 1to 10, which number when you multiply by itself will give you four apart from 2

4 0
3 years ago
GIVING BRAINLIEST Write an equation to represent the number puzzle. Use x as the
amid [387]

Answer:

It's C

Step-by-step explanation:

When I wrote it out I got x^2+7=7x-5

3 0
4 years ago
Find the rectangular coordinates of the point with the polar coordinates ordered pair 7 comma 2 pi divided by 3.
Morgarella [4.7K]

Answer:

\left(-\dfrac{7}{2},\dfrac{7\sqrt{3}}{2}\right).

Step-by-step explanation:

The given point is

\left(7,\dfrac{2\pi}{3}\right)

We need to find the rectangular coordinates of the given point.

If a polar coordinate is (r,\theta), then  

x=r\cos theta

y=r\sin theta

In the given point \left(7,\dfrac{2\pi}{3}\right),

r=7,\theta=\dfrac{2\pi}{3}

Now,

x=7\cos \dfrac{2\pi}{3}

x=7\cos \left(\pi-\dfrac{\pi}{3}\right)

x=-7\cos \left(\dfrac{\pi}{3}\right)

x=-7\left(\dfrac{1}{2}\right)

x=-\dfrac{7}{2}

and,

y=7\sin \dfrac{2\pi}{3}

y=7\sin \left(\pi-\dfrac{\pi}{3}\right)

y=7\sin \left(\dfrac{\pi}{3}\right)

y=7\left(\dfrac{\sqrt{3}}{2}\right)

y=\dfrac{7\sqrt{3}}{2}

Therefore, the required point is \left(-\dfrac{7}{2},\dfrac{7\sqrt{3}}{2}\right).

3 0
3 years ago
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