By replacing the point (-1, 4) into the first inequality y<= -(x)+4
4<= - (-1)+4
4<=1+4
4<=5 (this implies that this is the answer).
What you want to do is solve all of these so that it equals to 0 on one side. The ones that are a quadratic will have x^2
x^2 - 2x = 4x + 1
x^2 - 6x - 1 = 0
Yes this is a quadratic
x^3 - 6x^2 + 8 = 0
No this is not a quadratic because the highest power of x is to the power of 3
5x - 3 = 0
No it is not a quadratic because it does not have x^2
2x^2 + 12x = 0
Yes because there's x^2
5x - 1 = 3x + 8
2x - 9 = 0
No because no x^2
9x^2 + 6x - 3 = 0
Yes because there's x^2
If given the equation, you need to take the number beside the x and y and change their signs to get your point:
x - 8 (Take the -8 and make it +8)
y + 2 (Take the +2 and make it -2)
Your point is (8, -2)
