Answer:
<h2>231cm²</h2>
Step-by-step explanation:
First, let's find the surface area of both the triangles
5x3=15
So, the surface area of the triangles is 15 sq.cm
Now, let's find the surface area of the base (large rectangle in the middle)
12x8=?
10x8=80
2x8=16
80+16=96
12x8=96
So, the surface area of the base, is 96sq.cm
Now, let's find the surface area of both of the side rectangles
12x5=60
60x2=120
So, the surface area of the two side rectangles is 120sq.cm
Now, let's find the total surface area by adding all of our answers.
120+96=216
216+15=231
<h2>
So hence, the surface area of this net is 231cm²</h2>
Let
rA--------> radius of the circle A
rB-------> radius of the circle B
LA------> <span>the length of the intercepted arc for circle A
</span>LB------> the length of the intercepted arc for circle B
we have that
rA/rB=2/3--------> rB/rA=3/2
LA=(3/4)<span>π
</span>
we know that
if <span>Both circle A and circle B have a central angle , the ratio of the radius of circle A to the radius of circle B is equals to the ratio of the length of circle A to the length of circle B
</span>rA/rB=LA/LB--------> LB=LA*rB/rA-----> [(3/4)π*3/2]----> 9/8π
the answer is
the length of the intercepted arc for circle B is 9/8π
0.4219 Approximately .
Also HIIII
