The general formula for geometric series is tn = a×rⁿ⁻¹. In this question, a (or a1) is 3, and r is 1.1, therefore the first ten terms would be 3×1.1⁰ (3) , 3×1.1¹ (3.3), 3×1.1² (3.63) and so on up until you get to 3×1.1⁹ or 7.07.
Answer:
It makes sense at the beginning, but I'm sure that there's a second part??
Step-by-step explanation:
Sorry love
Answer:9
Step-by-step explanation:
Find the prime factorization of 72
72 = 2 × 2 × 2 × 3 × 3
Find the prime factorization of 135
135 = 3 × 3 × 3 × 5
To find the GCF, multiply all the prime factors common to both numbers:
Therefore, GCF = 3 × 3
GCF = 9
<span>P(9,12): For all intents and purposes, the hypotenuse is "r", the opposite side is "y", and the adjacent side is "x".
x = 9 (from the P(9,12))
y = 12 (also from the point)
Using the Pythagorean Theorem, you find out that r = 15.
Therefore, since cos θ = x/r
cos θ = 9/15 or 3/5
Answer: 3/5</span>