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3 years ago

PLEASE ANSWER

1 answer:

8 0

$\text{Difference of squares}\ a^2-b^2:\\\\4x^2-16=2^2x^2-4^2=(2x)^2-4^2\\\\\text{Difference of cubes}\ a^3-b^3:\\\\8x^3-1=2^3x^3-1^3=(2x)^3-1^3$

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2/5 x 3 as a fraction

Svet_ta [14]

Answer:

1 1/5

Step-by-step explanation:

2/5 x 3 as a Fraction = 1 1/5

Improper Fraction = 6/5

Mixed Number = 1 1/5

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There are 210 different groups. Hope it help!

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Use the graph of the line to answer each question

scoundrel [369]

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3 years ago

3 intersecting lines are shown. A line contains points E, D, A, and B. Another line intersects the line at point A and contains

GREYUIT [131]

Answer:

The one with arrows are the answers

->Line segment E B is bisected by Line segment D F .

->A is the midpoint of Line segment F C .

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Step-by-step explanation:

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Find [5(cos 330 degrees + I sin 330 degrees)]^3

earnstyle [38]

Given a complex number in the form:
$z= \rho [\cos \theta + i \sin \theta]$
The nth-power of this number, $z^n$ , can be calculated as follows:

- the modulus of $z^n$ is equal to the nth-power of the modulus of z, while the angle of $z^n$ is equal to n multiplied the angle of z, so:
$z^n = \rho^n [\cos n\theta + i \sin n\theta ]$
In our case, n=3, so $z^3$ is equal to
$z^3 = \rho^3 [\cos 3 \theta + i \sin 3 \theta ] = (5^3) [\cos (3 \cdot 330^{\circ}) + i \sin (3 \cdot 330^{\circ}) ]$ (1)
And since
$3 \cdot 330^{\circ} = 990^{\circ} = 2\pi +270^{\circ}$
and both sine and cosine are periodic in $2 \pi$ , (1) becomes
$z^3 = 125 [\cos 270^{\circ} + i \sin 270^{\circ} ]$

6 0

3 years ago