We write an inequality:
This equation cannot be solved using trivial methods found in high-school classes, so we resort to graphical examination.
is a linear function while
is an exponential one (with limit zero as
approaches
). We see that
at approximately
and
.
Indeed, using a computer algebra system such as the ones on modern TI calculators and on many internet sites gives equality at
. By observing our graph, we see that
when
or
.
Answer:
1767 cm³
Step-by-step explanation:
We can use volume V = 4/3 π r³
We have diameter of 15 cm. To get radius, we need to divide diameter by 2.
r = 7.5 cm
So now plug in r = 7.5 then calculate V:
V = 4/3 π ( 7.5 )³
V = 4/3 π * 421.875 ≈ 1767.145 ≈ 1767
Hope this helps.
Answer:
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Step-by-step explanation:
Answer:
The value of Car B will become greater than the value of car A during the fifth year.
Step-by-step explanation:
Note: See the attached excel file for calculation of beginning and ending values of Cars A and B.
In the attached excel file, the following are used:
Annual Depreciation expense of Car A = Initial value of Car A * Depreciates rate of Car A = 30,000 * 20% = 6,000
Annual Depreciation expense of Car B from Year 1 to Year 6 = Initial value of Car B * Depreciates rate of Car B = 20,000 * 15% = 3,000
Annual Depreciation expense of Car B in Year 7 = Beginning value of Car B in Year 7 = 2,000
Conclusion
Since the 8,000 Beginning value of Car B in Year 5 is greater than the 6,000 Beginning value of Car A in Year 5, it therefore implies that the value Car B becomes greater than the value of car A during the fifth year.
Answer:
-4y^2 - 2y + 10
Step-by-step explanation:
