Given that the ball has a thickness of 1 cm and the radius at the outside is 5 cm, thus the radius from inside is 5 - 1 = 4cm.
The <span>approximate volume of rubber used to make the ball is given by the volume of the ball at the outside surface minus the volume of the ball at the inside surface.
i.e.
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<span>

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Answer:
B :)
Step-by-step explanation:
<h3>Jason bought 20 stamps of $0.41 each and 8 postcards of $0.26 each.</h3>
<em><u>Solution:</u></em>
Let stamps be s and postcards be p
Given that,
The number of stamps was 4 more than twice the number of postcards
s = 4 + 2p -------- eqn 1
Jason bought both 41-cent stamps and 26-cent postcards and spent $10.28
41 cent = $ 0.41
26 cent = $ 0.26
Therefore,

0.41s + 0.26p = 10.28 --------- eqn 2
Substitute eqn 1 in eqn 2
0.41(4 + 2p) + 0.26p = 10.28
1.64 + 0.82p + 0.26p = 10.28
1.08p = 10.28 - 1.64
1.08p = 8.64
Divide both sides by 1.08
p = 8
Substitute p = 8 in eqn 1
s = 4 + 2(8)
s = 4 + 16
s = 20
Thus Jason bought 20 stamps and 8 post cards
Answer:
x^4
Step-by-step explanation:
The expression can be simplified to (x^2)^2. Using an exponent rule, you multiply the two exponents together to get 4. The answer is x^4
Answer:
f(0) = g(0)
Step-by-step explanation:
- if a function h(x) passes through [a,b] then it can be said that h(a)=b.
- given that, g(x) passes through (-2,0) and (0,4)
so, g(-2)=0, g(0)=4.
- f(x) passes through (0,4) and (2,0)
so, f(2)=0, f(0)=4.
- so, first option is correct.