Answer:
11.04 in taylor brown
Step-by-step explanation:
Answer:

Step-by-step explanation:
<u>Solving Equations Using Successive Approximations</u>
We need to find the solution to the equation

where


The approximation has been already started and reached a state for x=2.5 where


The difference between the results is 0.25, we need further steps to reach a good solution (to the nearest tenth)
Let's test for x=2.4


The new difference is -0.2+0.24=0.04
It's accurate enough, thus the solution is

Answer:
approximately 9
Step-by-step explanation:
6 squared (36) plus 8 squared (64) is 84, and the square root of that is about 9
Answer:
-2.3
Step-by-step explanation:
Answer:
1.61428571429
Step-by-step explanation:
That would be about 1.62. You do 3 5/7-2 1/10. That would equal to 1.61428571429.