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3 years ago

Round the values below to the nearest hundredths

Mathematics

2 answers:

Serhud [2]3 years ago

7 0

To round it to hundreths, you need to look at the thousandths place.

3.23543

Since the thousandths place is 5, you round up.

3.23543 ↑ ≈ 3.24

89.49234

Since the thousands place is below 5, you round down.

89.49234 ↓ ≈ 89.49

Margarita [4]3 years ago

3 0

for the first answer:

3.23543 rounds to 3.24

for the second answer:

89.49234 rounds to 89.49

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WILL GIVE BRAINLIEST!!

MA_775_DIABLO [31]

given a polynomial with factor (x - a)

Then x = a is a root of the polynomial and f(a) = 0

(1)

(x+ 2) is a factor , hence x = - 2 is a root

Evaluate the polynomial for x = - 2

f(- 2) = 5(- 2)³ + 8(- 2)² - 7(- 2) - 6 = - 40 + 32 + 14 - 6 = 0

Hence (x + 2 ) is a factor

(2)

If (x + 1) is a factor then x = - 1 is a root

5(- 1)³ + 8(-1)² - 7(- 1) - 6 = -5 + 8 + 7 - 6 = 4

Since f( - 1) ≠ 0

Then (x + 1) is not a factor

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4 years ago

Save me the headache

maxonik [38]

$(9\sin2x+9\cos2x)^2=81$

Taking the square root of both sides gives two possible cases,

$9\sin2x+9\cos2x=9\implies\sin2x+\cos2x=1$

$9\sin2x+9\cos2x=-9\implies\sin2x+\cos2x=-1$

Recall that

$\sin(\alpha\pm\beta)=\sin\alpha\cos\beta\pm\cos\alpha\sin\beta$

If $\alpha=2x$ and $\beta=\dfrac\pi4$ , we have

$\sin\left(2x+\dfrac\pi4\right)=\dfrac{\sin2x+\cos2x}{\sqrt2}$

so in the equations above, we can write

$\sin2x+\cos2x=\sqrt2\sin\left(2x+\dfrac\pi4\right)=\pm1$

Then in the first case,

$\sqrt2\sin\left(2x+\dfrac\pi4\right)=1\implies\sin\left(2x+\dfrac\pi4\right)=\dfrac1{\sqrt2}$

$\implies2x+\dfrac\pi4=\dfrac\pi4+2n\pi\text{ or }\dfrac{3\pi}4+2n\pi$

(where $n$ is any integer)

$\implies2x=2n\pi\text{ or }\dfrac\pi2+2n\pi$

$\implies x=n\pi\text{ or }\dfrac\pi4+n\pi$

and in the second,

$\sqrt2\sin\left(2x+\dfrac\pi4\right)=-1\implies\sin\left(2x+\dfrac\pi4\right)=-\dfrac1{\sqrt2}$

$\implies2x+\dfrac\pi4=-\dfrac\pi4+2n\pi\text{ or }-\dfrac{3\pi}4+2n\pi$

$\implies2x=-\dfrac\pi2+2n\pi\text{ or }-\pi+2n\pi$

$\implies x=-\dfrac\pi4+n\pi\text{ or }-\dfrac\pi2+n\pi$

Then the solutions that fall in the interval $[0,2\pi)$ are

$x=0,\dfrac\pi4,\dfrac\pi2,\dfrac{3\pi}4,\pi,\dfrac{5\pi}4,\dfrac{3\pi}2,\dfrac{7\pi}4$

5 0

3 years ago

Read 2 more answers

Lucky wom $500 in a lottery. She used 25% of her money to buy candies and saved the rest. How much money did she use? Write the

nirvana33 [79]

Answer:

1/8 1.25

Step-by-step explanation:

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3 years ago

Read 2 more answers

F(x) = a(x - h)power of 3 + k please describe what a, h and k do within our function.

Zarrin [17]

F(x) = a(x - h)³ + k

The parent graph is F(x) = x³

k - shifts the parent graph up k-units (or down if it is negative). This is also called a vertical shift.

h - shifts the parent graph to the right h-units (or left if it is negative). This is also called a horizontal shift.

a - stretches the parent graph vertically by a factor of "a"

Additonally, the coordinate (h, k) is the center/vertex of the graph.

6 0

3 years ago

The roof of the Terminal Tower is 709 feet above ground. A window washer dropped a bucket from the edge of the roof. How many se

Masja [62]

Answer:

6.64 seconds

Step-by-step explanation:

Given that:

Distance between roof of the terminal and ground = 709 feet

A bucket was dropped from the roof.

To find:

The time taken by the bucket to hit the ground?

Solution:

Distance traveled, $s$ = 709 feet

Initial velocity of the bucket, $u$ = 0 feet/sec (because initially it was at rest)

Acceleration of the bucket will be equal to acceleration due to gravity i.e.

$g$ or 32.1741 $ft/sec^{2}$

Let the time taken is $t$ seconds.

Formula for distance is given as:

$s = ut+\dfrac{1}{2}at^2$

Putting all the values:

$709 = 0 (t) + \dfrac{1}{2}(32.1741) t^2\\\Rightarrow 1418 = 32.1741 t^2\\\Rightarrow t^2 = 44.07\\\Rightarrow t \approx \bold{6.64\ sec}$

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3 years ago