Answer:
Step-by-step explanation:

Answer:
x = 50*e∧ -t/100
Step-by-step explanation:
We assume:
1.-That the volume of mixing is always constant 300 gallons
2.-The mixing is instantaneous
Δ(x)t = Amount in - Amount out
Amount = rate * concentration*Δt
Amount in = 3 gallons/ min * 0 = 0
Amount out = 3 gallons/min * x/ 300*Δt
Then
Δ(x)t/Δt = - 3*x/300 Δt⇒0 lim Δ(x)t/Δt = dx/dt
dx/dt = - x/100
dx/ x = - dt/100
A linear first degree differential equation
∫ dx/x = ∫ - dt/100
Ln x = - t/100 + C
initial conditions to determine C
t= 0 x = 50 pounds
Ln (50) = 0/100 * C
C = ln (50)
Then final solution is:
Ln x = - t/100 + Ln(50) or
e∧ Lnx = e ∧ ( -t/100 + Ln(50))
x = e∧ ( -t/100) * e∧Ln(50)
x = e∧ ( -t/100) * 50
x = 50*e∧ -t/100
Solution:
2(6+7)= 3(5+2)
Step ; 1 { Solving first Term i.e LHS }
LHS : 2 ( 6 + 7)
☞ 2 ( 13)
☞ 2 × 13
☞ 26
Now, RHS ; 3 ( 5 + 2)
☞ 3 ( 7)
☞ 21
From Equation 1 and 2, We can LHS and RHS are not Equal.
Therefore, 26≠ 21.
Answer:triangle BCD is similar to triangle ACE (side, angle C, side)
AC = 2 BC
therefore AE = 2 BD
therefore
4x+20 = 2 (3x+5) solve that
Step-by-step explanation:
Answer:
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